Answer:
The time taken by the projectile to hit the ground is 6.85 sec.
Explanation:
Given that,
Vertical height of cliff = 230 m
Distance = 300 m
Suppose, determine the time taken by the projectile to hit the ground.
We need to calculate the time
Using second equation of motion
Where, s = vertical height of cliff
u = initial vertical velocity
g = acceleration due to gravity
Put the value in the equation
Hence, The time taken by the projectile to hit the ground is 6.85 sec.
30 + 6 = 36
36/12 = 3
So, it would take it 3 hours to go 12 kms downstream.
Note that we added 30 and 6 because it was going downstream. If it was going upstream, then we would have had to subtract.
Gauss law states that the electric flux through any closed
surface is proportional to the net electric charge inside the surface. This is
expressed mathematically in the form of:
Φ = Q / εo
Where,
Φ = the electric flux = unknown (which we have to find for)
Q = the net electric charge = 5.0 µC = 5 E-6 C
εo = the permittivity of free space = a constant value =
8.85 E-12 C^2 / N m^2
Plugging in the values
into the equation will result in:
Φ = 5 E-6
C / (8.85 E-12 C^2 / N m^2)
Φ = 564,971.75 Wb = <span>5.6 x
10^5 Wb </span>
