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vredina [299]
3 years ago
7

I need the answer please

Physics
1 answer:
Tamiku [17]3 years ago
3 0

Answer:

,1) point B

2) point A

I hope it's helps you

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What color will the paper appear? Explain why?
Evgen [1.6K]

Answer:

The answer is B

Explanation:

6 0
3 years ago
A 1.2 x 103 kg racecar, with a velocity of 8 m/s, collides with an unsuspecting 80 kg honey badger who is standing
aalyn [17]

Answer: 90 m/s

Explanation:

Given

mass of racecar M=1.2\times10^3\ kg

velocity of racecar u=8\ m/s

mass of still honeybadger m=80\ kg

after collision race car is traveling at a speed of v_1=2\ m/s

conserving linear momentum

Mu+m\times0=Mv_1+ mv_2\quad[v_2=\text{velocity of honeybadger after colllision}]

1.2\times10^3\times8+0=1.2\times10^3\times2+80\times v_2

1.2\times10^3(8-2)=80v_2\\v_2=\frac{7.2\times10^3}{80}=90\ m/s

4 0
3 years ago
What is the amplitude of the wave shown in the diagram?
Marina86 [1]
The amplitude is from the absolute value of the 0 point on the y-axis to the highest(peak) or lowest(troph) point of the wave. In this question, 3cm is the highest and -3cm is the lowest, so the amplitude is 3cm.
4 0
3 years ago
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Gulls are often observed dropping clams and other shellfish from a height to the rocks below, as a means of opening the shells.
kumpel [21]

Answer:

v = 17.71 m / s

Explanation:

We can work this exercise with the kinematics equations. In general the body is released so that its initial velocity is zero, the acceleration of the acceleration of gravity

                v² = v₀² - 2 g (y -y₀)

                v² = 0 - 2g (y -y₀)

when it hits the stone the height is zero and part of the height of the seagull I

              v² = 2g y₀

              v = Ra (2g i)

let's calculate

              v =√ (2 9.8 16)

              v = 17.71 m / s

8 0
3 years ago
I’m ugly ain’t I ??????
olga55 [171]
Aw don’t say that! I’m sure your beautiful:)
7 0
3 years ago
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