To solve this problem we will apply the concepts related to angular resolution based on wavelength and the slit width at this case of the cat's pupils. This relationship is given as,
Here,
= Wavelength
a = Slit width
Therefore the angular resolution is
Answer:
41.8° to the vertical ( west of North) , 44.6 s
Explanation:
Using Pythagoras theorem, taking the direction it must go line as the hypotenuse
vh² = vs² + vd² vs is the speed of the stream, vh is the speed in the direction it must go to the vertical and vd is the speed going directly north
3 ² = 2² + vd²
9 - 4 = vd²
√5 = vd
2.24 m/s = vd which is the resultant speed
the direction it will go = tan θ = 2 / 2.24
θ = tan⁻¹(2 / 2.24) = 41.8° to the vertical ( west of North)
b)t = distance / v = 100 / 2.24 = 44.6 s
Answer:
phase difference = π / 2
constructive interference
Explanation:
Given data
wavelength = 420 nm
1st beam = 105 nm
path difference = 105 nm
to find out
phase difference and interference pattern of the two beams
solution
we use here equation of phase difference that is
phase difference = 2π / wavelength × Δx
put here value
phase difference = 2π / 420 × 105
phase difference = π / 2
and
we know that here path difference Δx is the integral multiple of the wavelength so it will be constructive interference
Δx is wavelength / 4
F=ma where f is force, m is mass, and a is acceleration.
The net force is 40-24=16N and the box is 8kg.
You can rearranage f=ma to make a the subject by dividing by m, so f/m=a
16/8=2m/s^2