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meriva
3 years ago
14

Which of the following is a combustion reaction?

Chemistry
1 answer:
Rina8888 [55]3 years ago
7 0
The answer is b it is a combustion reaction
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For each solution, calculate the initial and final pH after the addition of 0.010 mol of NaOH.
Murljashka [212]

Answer:

A. 12.6

B. 4.05

C. 10.93

Explanation:

A. 0.010mol of NaOH in 250.0mL gives a concentration of 0.04M NaOH = 0.04M OH⁻

pOH = -log [OH⁻] = 1.398

pH = 14-pOH = <em>12.6</em>

<em></em>

B. The reaction of NaOH with HCHO₂ is:

NaOH + HCHO₂ → H₂O + CHO₂⁻ + Na⁺

Initial moles of CHO₂⁻ and HCHO₂ are:

CHO₂⁻ = 0.250L × (0.275mol/L) = 0.06875moles

HCHO₂ = 0.250L × (0.195mol/L) = 0.04875moles

After reaction:

CHO₂⁻ = 0.06875moles + 0.010mol = 0.07875mol

HCHO₂ = 0.04875moles - 0.010mol = 0.03875mol

Using H-H equation (pKa of this buffer: 3.74)

pH = 3.74 + log [CHO₂⁻] / [HCHO₂]

pH =  3.74 + log [0.07875mol] / [0.03875mol]

<em>pH = 4.05</em>

<em></em>

C. The reaction of NaOH with CH₃CH₂NH₃Cl is:

NaOH + CH₃CH₂NH₃Cl → H₂O + CH₃CH₂NH₂ + Cl⁻ + Na⁺

Initial moles of CH₃CH₂NH₃Cl and CH₃CH₂NH₂ are:

CH₃CH₂NH₃Cl = 0.250L × (0.235mol/L) = 0.05875moles

CH₃CH₂NH₂ = 0.250L × (0.255mol/L) = 0.06375moles

After reaction:

CH₃CH₂NH₃Cl = 0.05875moles - 0.010mol = 0.04875mol

CH₃CH₂NH₂ = 0.06375moles + 0.010mol = 0.07375mol

Using H-H equation (pKa of this buffer: 10.75)

pH = 10.75 + log [CH₃CH₂NH₂] / [CH₃CH₂NH₃Cl]

pH =  10.75 + log [0.07375mol] / [0.04875mol]

<em>pH = 10.93</em>

8 0
3 years ago
Which of the following suggests that a physical change has taken place in an ice cube
zaharov [31]
The melting of the ice cube indicates physical change has taken place
7 0
3 years ago
How many atoms are in 0.625 moles of ge (atomic mass = 72.59 amu)?
lord [1]
0.625 moles of ge X 6.02x10^23 atoms/ 1 mol of ge equal to 3.76x10^23 atoms of ge, just times with Avogadro.
8 0
3 years ago
Read 2 more answers
What is the molar mass of Al2(SO4)3
Allisa [31]

342.15 g/mol is the molar mass of Al2(SO4)3 Aluminium sulfate, This is what I found I hope this is right. Hope this helps;)

5 0
3 years ago
Read 2 more answers
What is the molarity of 60.0 grams of NaOH dissolved in 750 milliliters of water?
Bumek [7]

<u>Answer:</u>

The correct answer option is B) 2.0 M.

<u>Explanation:</u>

We are given the number of grams of NaOH (Sodium Chloride) which are dissolved in 750 milliliters of water and we are to find its molarity.

We know the formula of molarity:

<em>Molarity =  (mass * 1000) / (volume * molecular mass)  </em>

Volume = 750 ml = 750 cm^3

Molecular mass = 40  

Mass = 60 grams

Substituting these values in the above formula:

Molarity = \frac{(60*1000)}{750*40} = 2.0 M

8 0
3 years ago
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