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3 years ago

How do I shift the function a(x)=|x|+3 2 units to the right to the right. This is due today please help

Mathematics

1 answer:

CaHeK987 [17]3 years ago

8 0

Answer:

QUESTION:

How do I shift the function a(x)=|x|+3 2 units to the right?

ANSWER:

Try Math___way I always go there for help when no one can help me here. Just type in your math question and you get instant answers and an explanation.

Step-by-step explanation:

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PPLSS I DONT WANNA FAIL simplify 7÷ 1/2

katen-ka-za [31]

The answer is 14.

a number divided by 1/2 will equal that number times 2

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4 years ago

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(04.05 LC)

Komok [63]

correct answer is option d.

Step-by-step explanation:

Here, we have The following expression to check Which of the following is a polynomial with roots: −square root of 3 , square root of 3, and 2 :

a. x3 + 3x2 − 5x − 15

For $-\sqrt{3}$ , $x^{3} + 3x^{2} -5x -15$ ⇒ $(-\sqrt{3}) ^{3} + 3(-\sqrt{3} )^{2} -5(-\sqrt{3} ) -15$ $\neq 0$ . So, this isn't the one. We move on further!

b. x3 + 2x2 − 3x − 6

For $-\sqrt{3}$ , $x^{3} + 2x^{2} -3x -6$ ⇒ $(-\sqrt{3}) ^{3} + 2(-\sqrt{3} )^{2} -3(-\sqrt{3} ) -6$ = 0 .

For $\sqrt{3}$ , $x^{3} + 2x^{2} -3x -6$ ⇒ $(\sqrt{3}) ^{3} + 2(\sqrt{3} )^{2} -3(\sqrt{3} ) -6$ = 0.

For 2 , $x^{3} + 2x^{2} -3x -6$ ⇒ $(2) ^{3} + 2(2)^{2} -3(2 ) -6$ $\neq 0$ . So, this isn't the one. We move on further!

c. x3 − 3x2 − 5x + 15

For $-\sqrt{3}$ , $x^{3}- 3x^{2} -5x -15$ ⇒ $(-\sqrt{3}) ^{3}- 3(-\sqrt{3} )^{2} -5(-\sqrt{3} ) -15$ $\neq 0$ . So, this isn't the one. We move on further!

d. x3 − 2x2 − 3x + 6

For $-\sqrt{3}$ , $x^{3} - 2x^{2} -3x +6$ ⇒ $(-\sqrt{3}) ^{3} - 2(-\sqrt{3} )^{2} -3(-\sqrt{3} ) +6$ = 0 .

For $\sqrt{3}$ , $x^{3} - 2x^{2} -3x +6$ ⇒ $(\sqrt{3}) ^{3} -2(\sqrt{3} )^{2} -3(\sqrt{3} ) +6$ = 0.

For 2 , $x^{3} - 2x^{2} -3x +6$ ⇒ $(2) ^{3} - 2(2)^{2} -3(2 ) +6$ = 0.

Therefore, correct answer is option d.

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