Answer:
Part A: Option 2, A: Anna’s answer is incorrect. She correctly factored out 5x, but incorrectly identified a and b, so her answer cannot be correct.
Part B: Option 3, B: 5x(x+2)(x^2−2x+4)
Step-by-step explanation:
p(x) = 5x^4 + 40x
p(x) = 5x(x^3 + 8)
p(x) = 5x(x + 2)(x^2 - 2x + 4)
Part A: Option 2, A: Anna’s answer is incorrect. She correctly factored out 5x, but incorrectly identified a and b, so her answer cannot be correct.
Part B: Option 3, B: 5x(x+2)(x^2−2x+4)
To answer this, set up a system of equations. What we know is that
5x + 2y = 100
And...
x+y=38
x represents the unknown number of 5 points questions
y represents the unknown number of 2 point questions
In my opinion the easiest way to solve this is to use substitution (that is when you find out the value of one variable, either x or y, and substitute that value as the variable).
So,
x+y=38
Subtract x from both sides
y=38-x
Now, plug (38-x) in as y in the other equation.
5x + 2(38-x) = 100
5x + 76-2x= 100
3x+76=100
3x=24
x=8
Now that you know that x=8, you can solve for y.
5x+2y=100
5(8)+2y=100
40+2y=100
2y=60
---- ------
2 2
y=30
X=8
Y=30
There are 8 five point questions on the test and 30 two point questions on the test
-19x-11 should be the answer... if the 19 and x aren’t combined then the answer is x-30
Answer:
Tara should consider colleges with lower expected total costs.
She should consider living at home to avoid room and board costs.
She should create a savings plan.
She should maximize scholarship potential.
Step-by-step explanation:
Tara should consider colleges with lower total costs, and also consider living in her parents' home to avoid room and board costs, as this would allow her to continue studying on a low budget.
You should create a savings plan, if you have some money saved, this allows you to earn interest to help pay for your studies.
You should maximize the potential of the scholarships, learning about all those you can apply to and managing your resources to acquire them.
The value of 
and a = 184
We let O be the centre, A₁ A A₂ , B₁ B B₂ represent the chords with length 10, 14 respectively.
Connecting the endpoints of the chords with the centre, we have several right triangles. However, we do not know whether the two chords are on the same side or different sides of the centre of the circle.
By the Pythagorean Theorem on Δ OBB₁,
we get x^2 + 7^2 = r^2
⇒ x = 
, where x is the length of the other leg. Now the length of the leg of Δ OAA₁ is either 6 + x or 6 - x depending whether or not A₁A₂, B₁B₂ are on the same side of the center of the circle:
± ) + 5² = r²
12 ± 
= 0
Only the negative works here (thus the two chords are on opposite sides of the center), and solving we get x=1, r =
. The leg formed in the right triangle with the third chord is 3 - x = 2, and by the Pythagorean Theorem again,
⇒
a = 184
To learn more about Pythagoras theorem from the given link
brainly.com/question/343682
#SPJ4
