Answer:
Explanation:
1) No take-off possible
2) The downward force is greater than the upward force.
3) 2000 + 950 = 2950 N upward
The center of mass is given with this formula:
![x_c=\frac{\sum_{n=1}^{n=i}m_ix_i}{M}](https://tex.z-dn.net/?f=x_c%3D%5Cfrac%7B%5Csum_%7Bn%3D1%7D%5E%7Bn%3Di%7Dm_ix_i%7D%7BM%7D)
Velocity is:
![v=\frac{dv}{dt}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bdv%7D%7Bdt%7D)
So, for the velocity of the center of mass we have:
![\frac{dx_c}{dt}=\frac{\sum_{n=1}^{n=i}d(m_ix_i)}{Mdt}\\ v_c=\frac{\sum_{n=1}^{n=i}p_i}{M}\\](https://tex.z-dn.net/?f=%5Cfrac%7Bdx_c%7D%7Bdt%7D%3D%5Cfrac%7B%5Csum_%7Bn%3D1%7D%5E%7Bn%3Di%7Dd%28m_ix_i%29%7D%7BMdt%7D%5C%5C%0Av_c%3D%5Cfrac%7B%5Csum_%7Bn%3D1%7D%5E%7Bn%3Di%7Dp_i%7D%7BM%7D%5C%5C)
In our case it is:
answer would be C. multiply the input force.
Answer:
A) r= 4081.63m
B) Fc= 519.205 kN
Explanation:
Given
![m=60.000 lf *\frac{1kg}{0.453lb}=13245.033 Kg](https://tex.z-dn.net/?f=m%3D60.000%20lf%20%2A%5Cfrac%7B1kg%7D%7B0.453lb%7D%3D13245.033%20Kg)
![V=400\frac{m}{s}](https://tex.z-dn.net/?f=V%3D400%5Cfrac%7Bm%7D%7Bs%7D)
![a=4*g=4*9.8\frac{m}{s^{2}}=39.2\frac{m}{s^{2}}](https://tex.z-dn.net/?f=a%3D4%2Ag%3D4%2A9.8%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%3D39.2%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D)
A)
The radius of the circle is:
![a_{c}=\frac{V^{2}}{r}\\r=\frac{V^{2}}{a_{c}}\\r=\frac{(400)^{2}}{39.2\frac{m}{s^{2}}}\\r=4081.63 m](https://tex.z-dn.net/?f=a_%7Bc%7D%3D%5Cfrac%7BV%5E%7B2%7D%7D%7Br%7D%5C%5Cr%3D%5Cfrac%7BV%5E%7B2%7D%7D%7Ba_%7Bc%7D%7D%5C%5Cr%3D%5Cfrac%7B%28400%29%5E%7B2%7D%7D%7B39.2%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%7D%5C%5Cr%3D4081.63%20m)
B)
The centripetal force
![F_{c}=m*a_{c}\\F_{c}=13245.033kg*39.2\frac{m}{s^{2}}\\F_{c}=519205.29N\\F_{c}=519.205 kN](https://tex.z-dn.net/?f=F_%7Bc%7D%3Dm%2Aa_%7Bc%7D%5C%5CF_%7Bc%7D%3D13245.033kg%2A39.2%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%5C%5CF_%7Bc%7D%3D519205.29N%5C%5CF_%7Bc%7D%3D519.205%20kN)
C)
The force of lift according to Bernoulli law the force of lift is equal to the force make the F-14 jet flying
Equation:
![F_{lift}=\frac{1}{2}*A*p*(V)^{2}](https://tex.z-dn.net/?f=F_%7Blift%7D%3D%5Cfrac%7B1%7D%7B2%7D%2AA%2Ap%2A%28V%29%5E%7B2%7D)
p=density of the air in the moment the jet in flying ≅1-1.5 and the area is going to be the area of the wings where is the force of lift acting have to be more that Fc
Answer:
I believe the answer is 2.5 N.......