Answer:
The motion of the atoms should vary depending on the state.
In this case, according to the given information about the oxidation numbers anf the compounds given, it turns out possible to figure out the oxidation number of manganese in both MnI2, manganese (II) iodide and MnO2, manganese (IV) oxide, by using the concept of charge balance.
Thus, we can define the oxidation state of iodine and oxygen as -1 and -2, respectively, since the former needs one electron to complete the octet and the latter, two of them.
Next, we can write the following
, since manganese has five oxidation states, and it is necessary to calculate the appropriate ones:

Next, we multiply each anion's oxidation number by the subscript, to obtain the following:

Thus, the correct choice is Manganese has an oxidation number of +2 in Mnl2 and +4 in MnO2.
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Answer: 101 moles of oxygen are contained in the tank
Explanation:
According to ideal gas equation:
P = pressure of gas = 204.047 atm
V = Volume of gas = 12.0 L
n = number of moles = ?
R = gas constant =
T =temperature =
Thus 101 moles of oxygen are contained in the tank
Answer:
the second answer
Explanation:
just multiple 10²=10×10=100×7.6=760g
5 plates is the highest amount that can be served
There’s only 5 sandwiches so 7 is automatically ruled out, there’s 14 corn cobs and 5 sandwiches only need 10 so it works out