Answer:
Precipitation
Explanation:
Let's consider the balanced chemical equation between barium acetate and sodium carbonate to form barium carbonate and sodium acetate.
Ba(C₂H₃O₂)₂(aq) + Na₂CO₃(aq) → BaCO₃(s) + 2 NaC₂H₃O₂(aq)
Both products and reactants are salts. But, among the products, barium carbonate is solid. This allows us to classify it as a precipitation reaction.
The concentration of [Sn⁺²] will be calculated by first calculating the moles of SnCl₂ added as these moles will give us the moles of [Sn⁺²] ion.
Moles of SnCl₂ = molarity X volume = 0.04 X 2.60 = 0.104 milli moles [as volume is in mL]
The moles of [Sn⁺² = 0.104 mmol
the total volume in solution = volume due to MO + volume due to SnCl₂ + volume due to HCl + volume due to NaCl
Total volume = 8+2.60+5.43+3.73= 19.76 mL
Concentration = moles / volume
concentration [Sn⁺²] = 0.104mmol / 19.76 mL = 0.0053 mol / L
Answer:
13.9atm
Explanation:
Use Boyle's Law: P1V1 = P2V2
Manipulate the equation: P2 = P1V1/V2
Substitute the values: P2 = (1.31atm)(5.51L)/0.520L
P2 = 13.88096atm
Optionally round to 3 sig figs to get 13.9atm
Answer:
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