2 years ago

SCIENCE QUIZ PLZ HELP I WILL GIVE YOU BRAINLYEST

Chemistry

2 answers:

ddd [48]2 years ago

8 0

i will i am in 10 th grade and will be able to answer till that level only

marta [7]2 years ago

3 0

Answer:

hello

i cant see any question

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The Clausius- Clapeyron equation is :

$\ln (\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}\times (\frac{1}{T_1}-\frac{1}{T_2})$

where,

$P_1$ = vapor pressure of liquid at 373 K = 681 torr

$P_2$ = vapor pressure of liquid at normal boiling point = 760 torr

$T_1$ = temperature of liquid = ?

$T_2$ = normal boiling point of liquid = 373 K

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R = universal constant = 8.314 J/K.mole

Now put all the given values in the above formula, we get:

$\ln (\frac{760torr}{681torr})=\frac{40700J/mole}{8.314J/K.mole}\times (\frac{1}{T_1}-\frac{1}{373K})$

$T_1=369.907K\approx 369.9K$

Hence, the temperature of liquid is, 369.9 K

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