Answer:
2ErF3 +3Mg = 3MgF2 + 2Er
Explanation:
This is a single replacement equation where there are 2 metals. The bonds are broken and new bonds are formed again by Mg and F.
Er has a +3 charge and F has a -1 charge. You switch it around and you get ErF3. Then you add the second reactant, Mg. The product is MgF as stated, and Mg has a charge of +2 and F has -1. You switch it again and you get MgF2. Then the second product Er is there.
Now we have
ErF3+Mg=MgF2+Er
So we balance the equation because of the law of conservation of mass.
Make F equal, so we add the coefficents 2 and 3
2ErF3+Mg=3MgF2+Er
And now Mg and Er need balancing so
2ErF3+3Mg=3MgF2+2Er
Hope this helped
Answer:
3.51 g of oxygen per gram of gasoline is required.
Explanation:
Solution:
First of all we will write the balance chemical equation.
C8H18 + 12.5O2 → 8CO2 + 9H2O
This equation shows that,
1 mole of gasoline react with 12.5 mole of oxygen for complete burning.
mass of one mole of gasoline = 8×12 + 18×1 = 114 g
mass of 12.5 mole of oxygen = 12.5 (16×2) = 400 g
Formula:
mass of oxygen per gram of gasoline = (400 / 114) = 3.51
so, 3.51 g of oxygen require for per gram of gasoline.
Answer:
The number of protons you welcome
Explanation:
Because there to tiny to see
