Answer:
F=989.6 N
Explanation:
Given that
Diameter of shaft = 70 mm
Diameter of bearing sleeve =70.2 mm
So clearance h=0.1 mm
Speed V= 400 mm/s
Length of shaft = 250 mm
We know that
μ= 900 x 0.005 Pa-s
μ= 4.5 Pa-s
As we know that
From Newton's law of viscosity ,the shear stress given as follows
We also know that
Force = shear stress x area
Now by putting the values
So force
F= 18,000 x π x 0.07 x 0.25
F=988.6 N
Answer:
Explanation:
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Answer:
class helloSarah {
public static void main(String [] args) {
Name = "Hello Sarah";
System.out.print(Name);
}
}
Explanation:
<em>The question seem incomplete; However, since the program is incorrect, I'll assume the question is to correct the given code;</em>
The program segment was written in Java and the correct program is in the answer section
<u>See bold texts for line by line explanation </u>
This line declares the class name
<em>class helloSarah {</em>
This line declares the main method of the program
<em>public static void main(String [] args) {</em>
This line initializes string variable Name
<em>String Name = "Hello Sarah";</em>
This line prints the initialized variable
<em>System.out.print(Name);</em>
<em>}</em>
<em>}</em>
<em />
Answer:
Explanation:
Given that
L= 50 m
Pressure drop = 130 KPa
For Copper tube is 3/4 standard type K drawn tube
Outside diameter=22.22 mm
Inside diameter=18.92 mm
Dynamic viscosity for kerosene
Pressure difference given as
Where
L is length of tube
μ is dynamic viscosity
Q is volume flow rate
d is inner diameter of tube
ΔP is pressure drop
Now by putting the values
So flow rate is