Is there a picture or something?
Answer:
A. 
B. 151.2 V
C.
D. V = 302.4 V
Solution:
As per the question:
Area of the plates of the parallel plate capacitors, A = 
Charge on the plates of the capacitor, 
Now,
(A) To calculate the electric field strength, E when the separation distance, d = 1.00 mm = 
:
(B) To calculate potential difference between the plates:
(C) Electric field strength when spacing is 2 mm, i.e., 
:
Since, the above expression of the electric field shows that it does not depend on the separation distance between the plates thus it will remain same, i.e., 
(D) Potential difference across the capacitor when d = :
V = Ed = 
Answer:
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I believe a is the answer enjoy
Answer:
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