Answer:
Explanation:
Using the formula to calculate the maximum height
H = u²/2g
u is the initial velocity = 18m/s
g is the acceleration due to gravity = 9.81
H = 18²/2(9.81)
H = 324/19.62
H = 16.51m
The maximum height in which the ball reached from the ground = 85m + 16.51m = 101.5m
b) Time of fight = 2u/g
T = 2(18)/g
T = 36/9.81
T = 3.67s
It took the ball 3.67s later to reach the ground
3) To get the final velocity of the ball as it hits the ground, we need to calculate the horizontal component of the velocity,
Ux = Ucosθ
ux = 18cos 90 (angle of launch is 90 since the ball is thrown vertically upwards)
Ux = 18(0)
Ux = 0m/s
Hence the final velocity of the ball as it hits the ground is 0m/s
<span>2Kg50m/
s2.5m/
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Answer:
Explanation:
A.
Given:
Vo = 21 m/s
Vf = 0 m/s
Using equation of Motion,
Vf^2 = Vo^2 - 2aS
S = (21^2)/2 × 9.8
= 22.5 m.
B.
Given:
S = 22.5 + 21 mm
= 22.521 m
Vo = 0 m/s
Using the equation of motion,
S = Vo × t + 1/2 × a × t^2
22.521 = 0 + 1/2 × 9.8 × t^2
t^2 = (2 × 22.521)/9.8
= 4.6
t = 2.14 s
Answer:
V = 10m/s for the final velocity.
S = 10m for distance II.
Explanation:
Given the given information:
5m/s2 acceleration
2 seconds Equals time
Because the vehicle begins at rest, its initial velocity is 0m/s.
The first equation of motion would be used to get the ultimate velocity.
V = U + at
We have by substituting into the equation
V = 0 + 5*2
V = 0 + 10
V = 10m/s.
Now, to find the distance covered, we would use the second equation of motion.
S = ut + ½at²
S = 0*2 + ½*5*2²
S = ½*5*4
S = 20/2
S = 10m
The first statement is true, because the US worker can produce 10 more caps in the same amount of time as the French worker, the US has a comparative advantage when making caps.