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Ksenya-84 [330]
3 years ago
8

= Br = C Name is 1 , formula is

Chemistry
1 answer:
sergeinik [125]3 years ago
3 0

Answer:

yqujsbr

Explanation:

hejsudh2ihdg4 they t sjh5c4uSvreju5 aur bd84kskythddok6vr for

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A) How many grams of water are produced when 2.50 g of aluminum
egoroff_w [7]
The correct answer is 13 I just did it bro
5 0
3 years ago
Which two cell components deal with the same kind of chemical substance ( lipid, protein, enzyme, and so on)
geniusboy [140]

Answer:

Cell membrane and cytoplasm

Explanation:

Cell membrane is the layer that surronds the cell and it is made up of lipids and proteins. It is made up of a kind of fatty acids based lipids i.e phospholipids and sterols.

Cytoplasm is a thick fluid that is found in the cell membranes. It acts as buffer and protect cells organelles and DNA from damage. It is made up of water, p, lipids, proteins, inorganic salts, nucleic acids.

6 0
3 years ago
In the reaction 2H2O (1)+ 2Cl^- (aq)= H2(g)+Cl2 (g)+ 2OH^-(aq), which substance is reduced?
Oksanka [162]

Answer:- C. H

Explanations:- Reduction is gain of electron. In other words we could say that decrease in oxidation number is reduction.

As per the rules, oxidation number of hydrogen in its compounds is +1(except metal hydrides) and the oxidation number of oxygen in its compounds is -2.

The oxidation number in elemental form is zero.

In H_2O , the oxidation number of H is +1 and oxidation number of O is -2. Oxidation number of Cl in Cl^- is -1. On product side, the oxidation number of hydrogen in H_2 is zero and in OH^- the oxidation number of H is +1 and that of O is -2. Oxidation number of Cl in Cl_2 is 0.

From above data, Oxidation number of O is -2 on both sides so it is not reduced.

Oxidation number of Cl is changing from -1 to 0 which is oxidation.

Oxidation number of H is changing from +1 to 0 which is reduction.

So, the right choice is C.H

8 0
3 years ago
Write the following elements in increasing order of atomic radius.<br> Ca, Mg, Be, Sr
Free_Kalibri [48]

Answer:

In increasing order:

Sr, Ca, Mg, Br

6 0
3 years ago
Compared to the nucleus 5626fe, what is the density of the nucleus 112 48cd?
tia_tia [17]

For a comparison of the nucleus 5626fe, the density of the nucleus 112 48cd is mathematically given as the same.

n(Cd) / n(Fe)=1

<h3>What is the density of the nucleus 112 48cd?</h3>

Generally, the equation for the density  is mathematically given as

d=\frac{A}{4/3}\piR^3

Therefore

n(Cd) / n(Fe) = [A (Cd) / (A Fe) ] * [ R (Fe) / R (Cd)]^3

n(Cd) / n(Fe)= (112 / 56 ) * (1/1.26)3

n(Cd) / n(Fe)=1

In conclusion, The ratio of n(Cd) = n(Fe) is 1, hence same

Read more about density

brainly.com/question/14010194

8 0
2 years ago
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