You would want to make sure that you have controlled the variables properly, and if you determine that you did then you would repeat the experiment to be sure of the results.
Answer:
chemical symbol= Cl ( chlorine)
electrons= 17
2p electrons = 6
6) Na2 SO4
7)nonmetallic elements
10)mass
11) mole
* sorry I didn't know Q. 8/9
Answer:
The answer to your question is 0.64 M
Explanation:
Data
Sucrose C₁₂H₂₂O₁₁ mass = 7.633 g
volume = 25 ml
Molarity = ?
Process
1.- Calculate the molar weight of Sucrose
C₁₂H₂₂O₁₁ = (12 x 12) +(22 x 1) + (11 x 16)
= 144 + 22 + 176
= 342 g
2.- Calculate the moles of sucrose
342 g ------------------ 1 mol
7.633 g --------------- x
x = (7.633 x 1) / 342
x = 0.0223 moles
3.- Calculate the molarity
Molarity = moles / volume (L)
Molarity = 0.0223 / 0.035
Molarity = 0.64
