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3 years ago

An atom of fluorine has an atomic mass of 19 u. Keeping in mind that its atomic number is 9, what can you infer about this atom?

Chemistry

1 answer:

Oliga [24]3 years ago

8 0

The fluorine atom has a neutron number of 10 it also have 10 valence electrons

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Refer to the graph. the graph shows the progress of digestion as carbohydrates, fats, and proteins pass through the human digest

nika2105 [10]

3 protein may be the answer

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4 years ago

What is the molarity of a KF(aq) solution containing 3.0 mol of KF in 2.00L of solution?

sergeinik [125]

Answer : The molarity of $KF$ in the solution is 1.5 M.

Explanation : Given,

Moles of $KF$ = 3.0 mol

Volume of solution = 2.00 L

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

$\text{Molarity}=\frac{\text{Moles of }KF}{\text{Volume of solution (in L)}}$

Now put all the given values in this formula, we get:

$\text{Molarity}=\frac{3.0mol}{2.00L}=1.5mole/L=1.5M$

Therefore, the molarity of $KF$ in the solution is 1.5 M.

4 0

3 years ago

Substances which will glow in the dark after being exposed to sunlight are called:

nordsb [41]

It is called phosphorescent substances.

6 0

3 years ago

Read 2 more answers

As you add protons to the nucleus and you add more what happen

Lubov Fominskaja [6]

The more protons you add, the more positively charged the atom becomes
the charge of an atom determines what kind of an atom it is

7 0

4 years ago

A solution is created by dissolving 13.0 grams of ammonium chloride in enough water to make 295 mL of solution. How many moles o

Masja [62]

Answer:

(a) Moles of ammonium chloride = 0.243 moles

(b) $Molarity_{ammonium\ chloride}=0.824\ M$

Explanation:

(a) Mass of ammonium chloride = 13.0 g

Molar mass of ammonium chloride = 53.491 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{13.0\ g}{53.491\ g/mol}$

Moles of ammonium chloride = 0.243 moles

(b) Moles of ammonium chloride = 0.243 moles

Volume = 295 mL = 0.295 L ( 1 mL = 0.001 L)

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity_{ammonium\ chloride}=\frac{0.243}{0.295}$

$Molarity_{ammonium\ chloride}=0.824\ M$

Volume = ?

Molarity = 0.824 M

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$0.824\ M=\frac{0.0500}{Volume}$

Volume = 0.05 / 0.824 L = 0.06068 L = 60.68 mL

6 0

4 years ago