1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
DanielleElmas [232]
3 years ago
5

A current of 0.5 A flows in a 60 W light bulb when the voltage differences between the ends of the filament is 120 V. What is th

e resistance of the filament ?
Physics
1 answer:
LuckyWell [14K]3 years ago
7 0

Resistance = (voltage) / (current)

Resistance = (120 V) / (0.5 A)

<em>Resistance = 240 ohms</em>

<em></em>

Know what ?  There might be too much information given in this question.  I want to check, because it's possible that it might not even all fit together.

To calculate my answer, I only used the voltage and the current.  I didn't use the "60 watts", and I'm curious to know whether it even fits with the given voltage and current.

Power = (voltage) times (current).

Power = (120 V) times (0.5 A)

Power = 60 watts  

Well gadzooks and sure enough !  The three numbers given in the question all go together nicely.  

And not only THAT !

The answer could have been calculated by using ANY TWO of them.

You might be interested in
If you are given force and time, you can determine power if you can know watts energy joules distance
shepuryov [24]

Answer:

distance

Explanation:

Distance is the missing quantity. It is needed to estimate the amount of work done by a force, and afterwards it is used to estimate the power, which is the work done over the time it took to complete it.

8 0
3 years ago
Read 2 more answers
SOMEONE HELP ME PLEASE
mihalych1998 [28]

Explanation:

By the second law of Newton we get the relation

F = ma

5 0
3 years ago
Read 2 more answers
On planet Q the standard unit of volume is called guppi. Space travelers from Earth have determined that one liter = 38.2 guppie
ankoles [38]

Answer:

5730 guppies

Explanation:

1 liter= 38.2 guppies

150 liters= 150×38.2

8 0
3 years ago
A spring with spring constant 11.5 N/m hangs from the ceiling. A 490 g ball is attached to the spring and allowed to come to res
Natalija [7]

Answer:

The time constant is \tau = 17.5 \ s    

Explanation:

From the question we are told that

   The spring constant is  k = 11.5 \  N/m

   The mass  of the ball is  m_b  = 490 \ g  = 0.49 \ kg

   The amplitude of the  oscillation t the beginning is x =  6.70 cm = 0.067 \  m

    The amplitude after time t is  x_t = 2.20 cm = 0.022 \  m

    The number of oscillation is N  = 30

Generally the time taken to attain the second amplitude is mathematically represented as

       t  = N  *  T                                            Here  T is the period of oscillation

         t = N * 2\pi \sqrt{\frac{m}{k} }

=>     t = 30 * 2 * 3.142 *  \sqrt{\frac{ 0.490}{11.5} }

=>     t = 38.88 \  s

Generally the amplitude at time t is mathematically represented as

         x(t) = x e^{-\frac{at}{2m} }

Here a is the damping  constant so

 at  t = 38.88 \  s ,  x_t = 2.20 cm = 0.022 \  m

So  

     0.022 = 0.067 e^{-\frac{a * 38.88}{2 * 0.490} }

=>  0.3284 = e^{-\frac{a * 38.88}{2 * 0.490} }

taking natural log of both sides

=>  ln(0.3284 ) = -\frac{a * 38.88}{2 * 0.490} }    

=>   a = 0.028

Generally the time constant is mathematically represented as

    \tau = \frac{m}{a}      

=> \tau = \frac{0.490}{  0.028}    

=> \tau = 17.5 \ s    

4 0
3 years ago
Since the aluminum bar is not an isolated system, the second law of thermodynamics cannot be applied to the bar alone. Rather, i
max2010maxim [7]

Answer:

ΔS total ≥ 0 (ΔS total = 0 if the process is carried out reversibly in the surroundings)

Explanation:

Assuming that the entropy change in the aluminium bar is due to heat exchange with the surroundings ( the lake) , then the entropy change of the aluminium bar is, according to the second law of thermodynamics, :

ΔS al ≥ ∫dQ/T

if the heat transfer is carried out reversibly

ΔS al =∫dQ/T  

in the surroundings

ΔS surr ≥ -∫dQ/T = -ΔS al → ΔS surr ≥ -ΔS al = - (-1238 J/K) = 1238 J/K

the total entropy change will be

ΔS total = ΔS al + ΔS surr

ΔS total ≥ ΔS al + (-ΔS al) =

ΔS total ≥ 0

the total entropy change will be ΔS total = 0 if the process is carried out reversibly in the surroundings

4 0
3 years ago
Other questions:
  • HOW CAN I SOLVE THIS QUESTION? PLEASE HELP The movement of a locomotive piston in the cylinder is limited to 0.76 m. Assume that
    13·1 answer
  • A fishing rod is an example of a lever. Which diagram shows the correct positions of the input force, output force, and fulcrum
    6·2 answers
  • Please need help on this
    6·2 answers
  • Use Kepler’s third law and the orbital motion of Earth to determine the mass of the Sun. The average distance between Earth and
    7·2 answers
  • : The truck is to be towed using two ropes. Determine the magnitudes of forces FA and FB acting on each rope in order to develop
    11·1 answer
  • A cyclist slows down from 8m/s to 2m/s in 3 seconds. What is the<br> acceleration?
    11·2 answers
  • True or false? A consequence that decrease the likelihood that a behavior will occur is known as reinforcement
    8·1 answer
  • Please can someone solve this physics question with a good explenation.
    12·1 answer
  • Near the center of our galaxy, hydrogen gas is moving directly away from us in its orbit about a black hole. The electromagnetic
    12·1 answer
  • Which state of matter would be described as a highly energized charge particles with moving extremely fast
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!