Valence bond theory stating that a bond between two atoms is the strongest when the nuclei of the atoms are touching each other is true.
<h3>What is Valence bond theory?</h3>
This theory states that when two valence orbitals of two different atoms overlap on each other, the bond is usually strong.
The bond formed in this scenario is usually covalent which involves sharing of the valence electrons.
Read more about Valence bond theory here brainly.com/question/11625586
#SPJ1
The answer should be neutralization
Answer:
The mass we will get from AgCl is 0.839g
Explanation:
Hello!
Let's solve this!
The reaction is:
2AgC2H3O2 + MgCl2 ---> 2AgCl + Mg (C2H3O2) 2
The data we have are:
V1 = 75mL * (1L / 1000L) = 0.075L
M1 = 0.078M
V2 = 55mL * (1L / 1000mL) = 0.055L
M2 = 0.109M
The molarity formula is
M = mol / V
We calculate the moles of each compound:
molAgC2H3O2 = 0.075L * 0.078mol / L = 0.00585mol
molMgCl = 0.055L * 0.109M = 0.005995
We calculate the compound that is in excess, and then use the limiting reagent to calculate the amount of product we will obtain.
Since there are two Cl in MgCl2, this means that we have 0.01199 mol to produce the product, but we will only use 0.00585 mol which is the amount we have of AgC2H3O2. So MgCl is the excess reagent.
Then:
AgCl mass = 0.00585mol * (2mol AgCl / 2molAgC2H3O2) * (143.34g AgCl / 1mo AgCl) = 0.839gAgCl
The mass we will get from AgCl is 0.839g
Qué es la pregunta que estás preguntando?
At constant temperature, if the volume of the sample of gas increases to the given value, the pressure decreases to 0.92atm.
<h3>
Boyle's law</h3>
Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.
Boyle's law is expressed as;
P₁V₁ = P₂V₂
Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.
Given the data in the question question;
- Initial volume of the gas V₁ = 30.0mL = 0.03L
- Initial pressure of the gas P₁ = 1.53atm
- Final volume of the gas V₂ = 50.1mL = 0.0501L
- Final pressure of the gas P₂ = ?
We substitute our given values into the expression above to determine the new pressure.
P₁V₁ = P₂V₂
P₂ = P₁V₁ / V₂
P₂ = ( 1.53atm × 0.03L ) / 0.0501L
P₂ = 0.0459Latm / 0.0501L
P₂ = 0.92atm
Therefore, at constant temperature, if the volume of the sample of gas increases to the given value, the pressure decreases to 0.92atm.
Learn more about Boyle's law here: brainly.com/question/1437490