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Nat2105 [25]
3 years ago
15

PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST The actual subject is Science but they dont have that as a option in pick

a subject

Physics
1 answer:
Drupady [299]3 years ago
7 0
Not any one of them but the approximate value is 0.075 km/min
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1.) A projectile is launched at 32.1 m/s and 52.6 º above the horizontal. Determine the:
Mandarinka [93]

Answer:

a.) Maximum height of the projectile. =32.5m

b.) The time it takes to reach the maximum height=2.6s

c.) Time of flight=2.6s

d.) Range=99.5m

Explanation:

5 0
3 years ago
A motor-driven winch pulls a 50.0 kg student 5.00 m up the rope at a constant speed of 1.25 m/s. how much power does the motor u
nadya68 [22]
Power is the rate work done given by dividing work done by unit time. It is measured in watts equivalent to J/s.
In this case the force by the student is mg = 490 N (taking g as 9.8m/s²)
Work done is given by force × distance,
Therefore, Power =(force × distance)/ time, but velocity/speed =distance/time
Thus, Power = force × speed/velocity
                     = 490 N × 1.25
                     = 612.5 J/S (Watts)
Hence, power will be 612.5 Watts.
7 0
4 years ago
Which vector shows the velocity of the yo-yo at this moment?
Helga [31]

The vector which shows the velocity of the yo-yo at this moment is A and is denoted as option A.

<h3>What is Velocity?</h3>

This is referred to the rate of change of distance with time and the unit is metre per seconds.

A shows the direction of motion is same as the direction of velocity and is the tangent at that particular point hence why it was chosen as the most appropriate choice.

Read more about Velocity here brainly.com/question/6504879

#SPJ1

6 0
2 years ago
HELP ASAP! WHOEVER DOES THIS I WILL MARK U AS BRAINLIEST!
lbvjy [14]

Answer:

The Answer is A

Explanation:

<h3>Mark me as <em><u>Brainliest</u></em></h3>

<em>Pls </em>

<em>Thx </em>

<u><em>hope this helped</em></u>

3 0
3 years ago
N4M.6 A board has one end wedged under a rock having a mass of 380 kg and is supported by another rock that touches the bottom s
Hitman42 [59]

Answer:

it is safe to stand at the end of the table

Explanation:

For this exercise we use the rotational equilibrium condition

         Στ = 0

         W x₁ - w x₂ - w_table x₃ = 0

         M x₁ - m x₂ - m_table x₃ = 0

where the mass of the large rock is M = 380 kg and its distance to the pivot point x₁ = 850 cm = 0.85m

the mass of the man is 62 kg and the distance

            x₂ = 4.5 - 0.85

            x₂ = 3.65 m

the mass of the table (m_table = 22 kg) is at its geometric center

            x_{cm} = L/2 = 2.25 m

            x₃ = 2.25 -0.85

            x₃ = 1.4 m

let's look for the maximum mass of man

            m_{maximum} = \frac{ M x_1 -m_{table} x_3}{ x_2}

let's calculate

             m_{maximum} = \frac{ 380 \ 0.85 - 22 \ 1.4}{3.65}(380 0.85 - 22 1.4) / 3.65

             m_{maximum} = 80 kg

we can see that the maximum mass that the board supports without turning is greater than the mass of man

             m_{maximum}> m

consequently it is safe to stand at the end of the table

5 0
3 years ago
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