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Nat2105 [25]
3 years ago
15

PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST The actual subject is Science but they dont have that as a option in pick

a subject

Physics
1 answer:
Drupady [299]3 years ago
7 0
Not any one of them but the approximate value is 0.075 km/min
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A force of 8,480 N is applied to a cart to accelerate it at a rate of 26.5 m/s2. What is the mass of the cart?
Anni [7]
F=ma
8480=26.5m
m=8480/26.5
m=320
The mass of the cart is 320kg.
8 0
3 years ago
Read 2 more answers
2. What will be the extension of this spring if the load is a) 4N and b) 75 g?
Furkat [3]

Answer:

6

Explanation:

just add

7 0
3 years ago
Is the magnitude of the acceleration of the center of mass of spool A greater than, less than, or equal to the magnitude of the
Anon25 [30]

Answer:

The acceleration of the centre of mass of spool A is equal to the magnitude of the acceleration of the centre of mass of spool B.

Explanation:

From the image attached, the description from the complete question shows that the two spools are of equal masses (same weight due to same acceleration due to gravity), have the same inextensible wire with negligible mass is attached to both of them over a frictionless pulley; meaning that the tension in the wire is the same on both ends.

And for the acceleration of both spools, we mention the net force.

The net force acting on a body accelerates the body in the same direction as that in which the resultant is applied.

For this system, the net force on either spool is exactly the same in magnitude because the net force is a difference between the only two forces acting on the spools; the tension in the wire and their similar respective weights.

With the net force and mass, for each spool equal, from

ΣF = ma, we get that a = ΣF/m

Meaning that the acceleration of the identical spools is equal also.

Hope this Helps!

6 0
3 years ago
Find the kinetic energy of a bullet weighing 0.10 N if its velocity is<br> 2.0 X 103 m/s?
irina1246 [14]

The kinetic energy of the bullet is 20.4 kJ.

<u>Explanation:</u>

Kinetic energy of a bullet will be equal to the product of mass of the bullet with the square of velocity or speed of the bullet and then the half of that product value.

But here the mass of the bullet is not given, instead the weight of the bullet is given in terms of force. So from this, we have to first find the mass of the bullet.

We know that as per Newton's second law of motion, force is directly proportional to the product of mass and acceleration. So here the acceleration will be equal to the acceleration due to gravity as it is weight of the object.

So F = mg

0.10 N = m × 9.8

So ,the mass of the bullet is 0.0102 kg.

Now, we know the mass and velocity of the bullet is given as 2000 m/s.

So,

kinetic energy = \frac{1}{2} × m × v²

kinetic energy = 0.5 × 0.0102 × 2000 × 2000 = 20.4 kJ

Thus, the kinetic energy of the bullet is 20.4 kJ.

5 0
4 years ago
A steady device in each cycle converts 155 J of work to thermal energy that is released into a reservoir at 340 K. Part A Calcul
sukhopar [10]

Answer:

change in entropy is 3.3034 × 10^{22}  

Explanation:

give data

thermal energy Q  = 155 J

temperature T = 340 K

to find out

change in entropy

solution

we know change in entropy formula that is

change in entropy = Q / ( K×T )   ..............1

here K is boltzmann constant that is 1.38 × 10^{-23} kg-m²/s²

put these value in equation 1 we get

change in entropy = Q / ( K × T )

change in entropy = 155 / (  1.38 × 10^{-23}  × 340 )

change in entropy = 3.3034 × 10^{22}  

so change in entropy is 3.3034 × 10^{22}  

7 0
3 years ago
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