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4 years ago

14

If the ball hits olaf and bounces off his chest horizontally at 8.50 m/s in the opposite direction, what is his speed vf after t

he collision? express your answer numerically in meters per second.

1 answer:

Feliz [49]4 years ago

3 0

Answer:

16s/m

Explanation:

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A 750-kg automobile is moving at 16.8 m/s at a height of 5.00 m above the bottom of a hill when it runs out of gasoline. The car

anygoal [31]

Answer:h=19.4 m

Explanation:

Given

mass of automobile $m=750\ kg$

Initial height of automobile $h_o=5\ m$

Velocity at this instant $v=16.8\ m/s$

If the car stops somewhere at a height $h$

Thus conserving total energy we get

$K_i+U_i=K_f+U_f$

$\frac{1}{2}mv^2+mgh_o=\frac{1}{2}m(0)^2+mgh$

$\frac{v^2}{2g}+h_o=h$

$h=5+\frac{16.8^}{2\times 9.8}$

$h=5+14.4$

$h=19.4\ m$

6 0

3 years ago

Someone please help will mark as brainliest

forsale [732]

Getting it right because you do not want to spread false information. To be first isnt always the best, sure you might feel better being the first, but you won’t always get it right.

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3 years ago

If there are two photons with different energies, the one that has a higher energy (a) has the higher frequency (b) has the high

kozerog [31]

Answer:

(a) has the highest frequency

Explanation:

E = hf...where E(is the energy of a photon);h(is the planck's constant) and f is the frequency of the photon

Whereby this formula shows us that energy of a photon is directly proportional to its frequency

So hence if the energy is high then the frequency of the photon is also high

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A solid brass cylinder and a solid wood cylinder have the same radius and mass (the wood cylinder is longer). Released together

Lena [83]

Answer:

a. They will be tie

b. Win the wood cylinder

Explanation:

a.

The both cylinders will reach the bottom at the same time notice the relation in the equation in indepent of the length and both have the same radius and the same rotational inertia.

$I=\frac{1}{2}*m*r^2$

$a=\frac{g*sin(\beta)}{1+I_{com}/m*r^2}$

So both will be tie

b.

$a_{brass}=\frac{g*sin(\beta)}{1+I_{brass}/m*r^2}=a_{wood}=\frac{g*sin(\beta)}{1+I_{wood}/m*r^2}$

The acceleration of the wood cylinder is larger than the acceleration of the brass cylinder so the cylinder of wood will reach the bottom first

$a_{brass}$

So the wood win the race

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3 years ago

When the green arrow and solid red light is illuminated, __________?

otez555 [7]

<span>When the green arrow and solid red light is illuminated, </span>means you turn in the direction of the arrow.

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3 years ago