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Stells [14]
2 years ago
6

URGANT!!!!!!! NEED ANSWERS TODAY!!!!

Physics
1 answer:
natima [27]2 years ago
5 0
2H2 + O2 = 2H2O + Energy
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I don't know the answer can anybody help?
Anna007 [38]

We don't have enough information in the picture to answer that question.

The disembodied right hand could just as well grab the wire in the other direction, with the thumb pointing to the right.

Maybe if we knew WHY the hand is holding the wire in this direction, and what other electrical phenomenon may be involved, we might be able to say something about the current in the wire.

(Actually, we don't even know if it's a wire. It might be a soda straw, a coat hanger, or a pool cue.)

4 0
3 years ago
Considerable scientific work is currently under way to determine whether weak oscillating magnetic fields such as those found ne
VLD [36.1K]

Answer:

The the maximum emf is 2.52\times10^{-11}\ V

Explanation:

Given that,

Magnetic field B = 1.40\times10^{-3}\ T

Frequency = 60 Hz

Diameter = 7.8 μm

We need to calculate the maximum emf

Using formula of emf

\epsilon=NBA\omega

Where, N = number of turns

B= magnetic field

A = area

Put the value in to the formula

\epsilon=1\times1.40\times10^{-3}\times\pi\times(\dfrac{7.8\times10^{-6}}{2})^2\times2\times\pi\times60

\epsilon=2.52\times10^{-11}\ V

Hence, The the maximum emf is 2.52\times10^{-11}\ V

5 0
3 years ago
A ball is kicked at an angle of 30˚ with the ground. What should be the initial velocity of the
Hoochie [10]

Answer:

a.18.5 m/s

b.1.98 s

Explanation:

We are given that

a.Let  be the initial velocity of the ball.

Distance,x=30 m

Height,h=1.8 m

Substitute the values

Initial velocity of the ball=18.5 m/s

b.Substitute the value then we get

t=1.98 s

Hence, the time for the ball to reach the target=1.98 s

7 0
2 years ago
What is the frequency of a wave when it has a wavelength of 2.17 m and is travelling across a rope at a speed of 31 m/s?
VikaD [51]

Answer:

i) b. 14.3 Hz

ii) d. 0.4625 m/s

Explanation:

f = c / λ

f = frequency

c = speed

λ = wavelength

first question:

the given values,

λ = 2.17 m

c = 31 m/s

f = c / λ

f = 31 / 2.17

f = 14.28

∴ f = 14.3 Hz

second question:

given,

λ = 0.25 m

f = 1.85 Hz

f = c / λ

rearranging,

c = f × λ

c = 1.85 × 0.25

c = 0.4625

∴ c = 0.4625 m/s

(love your username, btw.)

4 0
3 years ago
Find the efficiency of a machine that does 800 J of work if the<br> input work is 2,000 J.
torisob [31]

Answer:

Efficiency: 0.4 (40%)

Explanation:

The efficiency of a simple machine is given by the ratio

\eta = \frac{W_{out}}{W_{in}}

where

W_{in} is the input work of the machine

W_{out} is the output work of the machine

For the machine in this problem, we have:

W_{out}=800 J is the output work

W_{in}=2000 J is the input work

Therefore, the efficiency of the machine is

\eta=\frac{800}{2000}=0.4

Which can be also written as percentage:

\eta=0.4\cdot 100 = 40\%

3 0
3 years ago
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