Question

A shunt regulator utilizing a zener diode with an incremental resistance of 8 ohm is fed through an 82-Ohm resistor. If the raw supply changes by 1.0 V, what is the correspondig change in the regulated outut voltage?

Answer 1

Answer:

$\triangle V_0=0.08V$

Explanation:

From the question we are told that:

Incremental resistance  $R=8ohms$

Resistor Feed $R_f=82ohms$

Supply Change $\triangle V=1$

Generally the equation for  voltage rate of change is mathematically given by

 $\frac{dV_0}{dV}=\frca{R}{R_1r_3}$

Therefore

 $\triangle V_0=\triangle V*\frac{R}{R_fR}$

 $\triangle V_0=1*\frac{8}{8*82}$

 $\triangle V_0=0.08V$