To find the mass and volume of irregularly shaped object. One can use the balance to find the weight, and to find the volume of the object water should be poured in the beaker and note the level of water.
Answer:
α = 5.75°
Explanation:
In this case, the problem states that both springs have identical lenghts and we also have theri constant. We want to know the angle of the rod with the horizontal. This can be found with the following expression:
sinα = Δx/L
α = sin⁻¹ (Δx/L) (1)
However, we do not have Δx. This can be found when half of the weight of the rod is balanced. In this way:
F₁ = k₁*x₁ ----> x₁ = F₁ / k₁ (2)
And the force is the weight in half so: F₁ = mg/2
Replacing in (2) we have:
x₁ = (1.3 * 9.8) / (2 * 58) = 0.1098 m
Doing the same thing with the other spring, we have:
x₂ = (1.3 * 9.8) / (2 * 36) = 0.1769 m
Now the difference will be Δx:
Δx = 0.1769 - 0.1098 = 0.0671 m
Finally, we can calculate the angle α, from (1):
α = sin⁻¹(0.0671 / 0.67)
<h2>
α = 5.75 °</h2>
Hope this helps
Let the key is free falling, therefore from equation of motion
.
Take initial velocity, u=0, so
.
As velocity moves with constant velocity of 3.5 m/s, therefore we can use formula
From above substituting t,
.
Now substituting all the given values and g = 9.8 m/s^2, we get
.
Thus, the distance the boat was from the point of impact when the key was released is 10.60 m.