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3 years ago

Determine the number of valence electrons in each of the following neutral atoms.

Chemistry

1 answer:

Harlamova29_29 [7]3 years ago

6 0

Answer:

Fluorine = 7 v.e.

Sulfur = 6 v.e.

Oxygen = 6 v.e.

Nitrogen = 5 v.e.

Carbon = 4 v.e.

Explanation:

Valence electrons can be easily determined by understanding groups (columns). Every element in. . .

column 3A (13) = 3 v.e.

column 4A (14) = 4 v.e.

column 5A (15) = 5 v.e.

column 6A (16) = 6 v.e.

column 7A (17) = 7 v.e.

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Dbv-qyag-dsc.join this now on meet

Rasek [7]

Answer:

Don't post any question if isn't related to the topic or to your homework or assignment.

Explanation:

7 0

2 years ago

In a titration of 47.41 mL of 0.3764 M ammonia with 0.3838 M aqueous nitric acid, what is the pH of the solution when 47.41 mL +

Volgvan

Answer: The pH of the solution is 1.136

Explanation:

To calculate the moles from molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

For ammonia:

Molarity of ammonia = 0.3764 M

Volume of ammonia = 47.41 mL = 0.04741 L (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$0.3764mol/L=\frac{\text{Moles of ammonia}}{0.04741L}\\\\\text{Moles of ammonia}=0.01784mol$

For nitric acid:

Molarity of nitric acid = 0.3838 M

Volume of ammonia = (47.41 + 10.00) mL = 57.41 mL= 0.05741 L

Putting values in above equation, we get:

$0.3838mol/L=\frac{\text{Moles of nitric acid}}{0.05741L}\\\\\text{Moles of nitric acid}=0.02203mol$

After the completion of reaction, amount of nitric acid remained = 0.022 - 0.0178 = 0.0042 mol

For the reaction of ammonia with nitric acid, the equation follows:

$NH_3+HNO_3\rightarrow NH_4NO_3$

At $t=0$ 0.0178 0.022

Completion 0 0.0042 0.0178

As, the solution of the reaction is made from strong acid which is nitric acid and the conjugate acid of weak base which is ammonia. So, the pH of the reaction will be based totally on the concentration of nitric acid.

To calculate the pH of the reaction, we use the equation:

$pH=-\log[H^+]$

where,

$[H^+]=\frac{0.0042mol}{0.05741L}=0.0731M$

Putting values in above equation, we get:

$pH=-\log(0.0731)\\\\pH=1.136$

Hence, the pH of the solution is 1.136

8 0

3 years ago

Help pls!!!!!!!!!!!!!

UkoKoshka [18]

Answer:

1. C + O₂ → CO₂

2. C + CO₂ → 2 CO

3. Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂

4 0

2 years ago

Titanium and chlorine react to form titanium(IV) chloride, like this:

leva [86]

Answer:

the value of equilibrium constant for the reaction is 8.5 * 10⁷

Explanation:

Ti(s) + 2 Cl₂(g) ⇄ TiCl₄(l)

equilibrium constant Kc = $\frac{1}{[Cl_2]^2}$

Given that,

We are given:

Equilibrium amount of titanium = 2.93 g

Equilibrium amount of titanium tetrachloride = 2.02 g

Equilibrium amount of chlorine gas = 1.67 g

We calculate the No of mole = mass / molar mass

mass of chlorine gas = 1.67 g

Molar mass of chlorine gas = 71 g/mol

mole of chlorine = 1.67 / 71

= 7.0L

Concentration of chlorine is = no of mole / volume

= 0.024 / 7

= 3.43 * 10⁻³M

equilibrium constant Kc = $\frac{1}{[Cl_2]^2}$

= $\frac{1}{[3.43 * 10^-^3]^2}$

= 8.5 * 10⁷

4 0

3 years ago

If an atom has 12 protons 12 neutrons, and 12 electrons, what is the charge of the atom?

Evgesh-ka [11]

I think the charge is +2
Hope this helps

6 0

2 years ago