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gogolik [260]
3 years ago
9

Determine the number of valence electrons in each of the following neutral atoms.

Chemistry
1 answer:
Harlamova29_29 [7]3 years ago
6 0

Answer:

Fluorine = 7 v.e.

Sulfur = 6 v.e.

Oxygen = 6 v.e.

Nitrogen = 5 v.e.

Carbon = 4 v.e.

Explanation:

Valence electrons can be easily determined by understanding groups (columns). Every element in. . .

column 3A (13) = 3 v.e.

column 4A (14) = 4 v.e.

column 5A (15) = 5 v.e.

column 6A (16) = 6 v.e.

column 7A (17) = 7 v.e.

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Does temperature change during a chemical reaction?​
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Explanation:

Not all the time, but temperature change can happen during a chemical reaction.

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An object has a weight of 5.10 Newtons (N) at sea level, where the acceleration due to gravity is 9.81 m/s2.
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Well, you could get the mass as m=\frac{G_0}{g_0} ad then g_1=\frac{G_1}{m}, where G_0 is the sea level weight, g_0 the sea level accel., g_1 the accel. above while G_1 the weight above.
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A ball is dropped from a height of 1.20 m and hits the floor. The ball compresses and then reforms to spring upwards from the fl
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Answer:

\large \boxed{\text{98 m$\cdot$s}^{-2}}

Explanation:

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v = \sqrt{2gh}

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v = -\sqrt{2 \times 9.807 \times 1.20} = -\sqrt{23.54} = -\textbf{4.85 m/s}

2. Velocity on rebound

The ball has enough upward velocity to reach a height of 0.86 m.

v = \sqrt{2 \times 9.807 \times 0.86} = \sqrt{16.87} =\textbf{4.11 m/s}

3. Acceleration

a = \dfrac{\Delta v}{\Delta t} = \dfrac{4.11 - (-4.85)}{ 0.091} = \dfrac{8.96 }{0.091} =\textbf{98 m$\cdot$s}^{\mathbf{-2}}\\\\\text{The acceleration while the ball is in contact with the floor is $\large \boxed{\textbf{98 m$\cdot$s}^{\mathbf{-2}}}$}

5 0
4 years ago
What are the products of the reaction below?:<br> calcium chloride+ silver nitrate
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3 years ago
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If 1. 3618 moles of AsF3 are allowed to react with 1. 0000 mole of C2Cl6, what would be the theoretical yield of AsCl3, in moles
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Answer:

AsF3:C2CI6

4:3

1.3618 moles: 1.02135 moles(1.3618÷4×3)

C2CI6 is the limting reagent

So the number of moles for AsCI3 is 0.817 moles( number of moles of the limting reagant) ÷3 ×4 (according to ratio by balancing chemical equation)=1.09 moles(3 s.f.)

or

Balanced equation

4AsF3 + 3C2Cl6 → 4AsCl3 + 3C2Cl2F4

Use stoichiometry to calculate the moles of AsCl3 that can be produced by each reactant.

Multiply the moles of each reactant by the mole ratio between it and AsCl3 in the balanced equation, so that the moles of the reactant cancel, leaving moles of AsCl3.

Explanation:

5 0
3 years ago
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