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3 years ago

Determine the number of valence electrons in each of the following neutral atoms.

Chemistry

1 answer:

Harlamova29_29 [7]3 years ago

6 0

Answer:

Fluorine = 7 v.e.

Sulfur = 6 v.e.

Oxygen = 6 v.e.

Nitrogen = 5 v.e.

Carbon = 4 v.e.

Explanation:

Valence electrons can be easily determined by understanding groups (columns). Every element in. . .

column 3A (13) = 3 v.e.

column 4A (14) = 4 v.e.

column 5A (15) = 5 v.e.

column 6A (16) = 6 v.e.

column 7A (17) = 7 v.e.

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What is the number of protons plus the number of neutrons in the nucleus of an atom equivalent to?

Kryger [21]

Answer:

Explanation:

b/c proton + neutron=mass number and

mass number - proton= neutron

7 0

2 years ago

Question 3) A 1.00 L buffer solution is 0.250 M in HF and 0.250 M in LiF. Calculate the pH of the solution after the addition of

Masja [62]

The pH of the solution after adding 0.150 moles of solid LiF is 3.84

Explanation:

We have the chemical equation,

HF (aq)+NaOH(aq)->NaF(aq)+H2O

To find how many moles have been used in this

c= n/V=> n= c.V

nHF=0.250 M⋅1.5 L=0.375 moles HF

Simillarly

nF=0.250 M⋅1.5 L=0.375 moles F

nHF=0.375 moles - 0.250 moles=0.125 moles

nF=0.375 moles+0.250 moles=0.625 moles

[HF]=0.125 moles/1.5 L=0.0834 M

[F−]=0.625 moles/1.5 L=0.4167 M

To determine the problem using the Henderson - Hasselbalch equation

pH=pKa+log ([conjugate base/[weak acid])

Find the value of Ka

pKa=−log(Ka)

pH=−log(Ka) +log([F−]/[HF]

pH= -log(3.5 x 10 ^4)+log(0.4167 M/0.0834 M)

pH=-log(3.5 x 10 ^4)+log(4.996)

pH= -4.54+0.698

pH=-(-3.84)

pH=3.84

The pH of the solution after adding 0.150 moles of solid LiF is 3.84

5 0

3 years ago

Need help answering

svp [43]

Answer:

Your answer would be E

Explanation:

4 0

2 years ago

An aqueous sodium acetate, NaC2H3O2 , solution is made by dissolving 0.395 mol NaC2H3O2 in 0.505 kg of water. Calculate the mola

liq [111]

Answer: The molality of $NaC_2H_3O_2$ solution is 0.782 m

Explanation:

Molality is defined as the amount of solute expressed in the number of moles present per kilogram of solvent. The units of molarity are mol/kg. The formula used to calculate molality:

$\text{Molality of solution}=\frac{\text{Moles of solute}}{\text{Mass of solvent (in kg)}}$ .....(1)

Given values:

Moles of $NaC_2H_3O_2$ = 0.395 mol

Mass of solvent (water) = 0.505 kg

Putting values in equation 1, we get:

$\text{Molality of }NaC_2H_3O_2=\frac{0.395mol}{0.505kg}\\\\\text{Molality of }NaC_2H_3O_2=0.782m$

Hence, the molality of $NaC_2H_3O_2$ solution is 0.782 m

8 0

3 years ago

When you put a bottle of juice in a cooler full of ice the juice gets cold that's because the cold transfers to the juice and sl

zubka84 [21]

Because the ice helps cool it up

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3 years ago