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max2010maxim [7]
3 years ago
15

Ca+Cl2-->CaCl2 Then, write balanced half-reactions describing the oxidation and reduction that happen in this reaction.

Chemistry
1 answer:
kompoz [17]3 years ago
8 0

Answer:

Oxidation half

Ca -----> Ca2+ +2elecyrons

Reduction half

Cl2 + 2electrons ------> 2Cl-

Explanation:

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Calculate the mass-to-mass ratio of 25.0 g of salt in 105 g of water. Work must be shown in order to earn credit.
Sveta_85 [38]

Answer:

0.23

Explanation:

  • It is known that, the mass to mass ratio of the salt to water

= (mass of salt / mass of water)

= (25.0 g / 105.0 g)

= 0.23

  • So, the answer is 0.23

4 0
3 years ago
Sarah is making a strawberry banana smoothie. She combines one banana, five strawberries, and a cup and a half of milk in a
NeTakaya

Answer:

homogeneous substance

8 0
3 years ago
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A buffer solution is made that is 0.347 M in H2C2O4 and 0.347 M KHC2O4.
irga5000 [103]

Answer:

1. pH = 1.23.

2. H_2C_2O_4(aq) +OH^-(aq)\rightarrow HC_2O_4^-(aq)+H_2O(l)

Explanation:

Hello!

1. In this case, for the ionization of H2C2O4, we can write:

H_2C_2O_4\rightleftharpoons HC_2O_4^-+H^+

It means, that if it is forming a buffer solution with its conjugate base in the form of KHC2O4, we can compute the pH based on the Henderson-Hasselbach equation:

pH=pKa+log(\frac{[base]}{[acid]} )

Whereas the pKa is:

pKa=-log(Ka)=-log(5.90x10^{-2})=1.23

The concentration of the base is 0.347 M and the concentration of the acid is 0.347 M as well, as seen on the statement; thus, the pH is:

pH=1.23+log(\frac{0.347M}{0.347M} )\\\\pH=1.23+0\\\\pH=1.23

2. Now, since the addition of KOH directly consumes 0.070 moles of acid, we can compute the remaining moles as follows:

n_{acid}=0.347mol/L*1.00L=0.347mol\\\\n_{acid}^{remaining}=0.347mol-0.070mol=0.277mol

It means that the acid remains in excess yet more base is yielded due to the effect of the OH ions provided by the KOH; therefore, the undergone chemical reaction is:

H_2C_2O_4(aq) +OH^-(aq)\rightarrow HC_2O_4^-(aq)+H_2O(l)

Which is also shown in net ionic notation.

Best regards!

4 0
3 years ago
How many molecules in 9.18 moles of C11H12O22
Setler [38]

Answer:

55.3 × 10²³ molecules

Explanation:

Given data:

Number of moles of C₁₁H₁₂O₂₂ = 9.18 mol

Number of molecules = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

For given data:

9.18 mol × 6.022 × 10²³ molecules /1 mol

55.3 × 10²³ molecules

5 0
3 years ago
Consider this reaction: KOH + HBr - KBr + H20<br> Which statement is most likely true about HBr?
Roman55 [17]

Answer: It turns blue litmus red

Explanation:

I just got it right on edge

7 0
2 years ago
Read 2 more answers
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