All categories

3 years ago

What Element am I?

Chemistry

1 answer:

rjkz [21]3 years ago

6 0

Answer:

The correct answer is - sulfur.

Explanation:

In the periodic table, there are 18 groups and 7 rows or periods arranged according to their atomic number or electronic configuration. In the question, it is mentioned that the desired element atomic mass is less than the atomic mass of the selenium which is 78.96, and more than oxygen which is 15.99 with 6 electron valence and present in the third row.

As it has 6 valency of electron it must be in the 16 group of the table that comprises the 6 valency and as it is located in the 3rd row it must be sulfur that also has an atomic mass between selenium and oxygen.

You might be interested in

in your notebook,write the appropriate tempo for the following actions.Then demostrate the actions then,demostrate the action in

pogonyaev

Answer:

cell :—

•They lack a well-defined nucleus, have a nucleoid instead.

•Usually have double-stranded, circular DNA.

•Do not have mitochondria.

Eukaryotic cell :—

•Have a well-defined nucleus enclosed in the nuclear membrane.

•Have a linear double-stranded nucleus.

•Mitochondria are present.

6 0

3 years ago

What substances can be separated into simpler substances only by chemical means?

Mnenie [13.5K]

A compound is a substance that can be separated into simpler substances only by chemical means.

6 0

3 years ago

How to make crystals using table salt?<br> Please help I"ll mark you as the BRAINLIEST!!!

Dafna11 [192]

Answer:

1.heat a pan of water with just a little bit of water,have a boil

2.chosse ure salt

3.stir in has much salt has u can than take the pan off the heat

4.pour the mix into a glass jar

5.tie a string to an objeet that can lay accross the top and put just the string in ure mix

Explanation oh and look at it everyday hope that helps

8 0

3 years ago

Oxygen is needed to produce energy in eukaryotic cells. Which organelle would you think needs oxygen the most

bezimeni [28]

Mitochondria need the most oxygen

5 0

4 years ago

48g of 02 produce how many grams of Al2O3

bixtya [17]

Taking into account the reaction stoichiometry, 102 grams of Al₂O₃ are formed when 48 grams of O₂ react.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

4 Al + 3 O₂ → 2 Al₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Al: 4 moles
O₂: 3 moles
Al₂O₃: 2 moles

The molar mass of the compounds is:

Al: 27 g/mole
O₂: 32 g/mole
Al₂O₃: 102 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Al: 4 moles ×27 g/mole= 108 grams
O₂: 3 moles ×32 g/mole= 96 grams
Al₂O₃: 2 moles ×102 g/mole= 204 grams

<h3>Mass of Al₂O₃ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 96 grams of O₂ form 204 grams of Al₂O₃, 48 grams of O₂ form how much mass of Al₂O₃?

$mass of Al_{2} O_{3} =\frac{48 grams of O_{2} x204 grams of Al_{2} O_{3}}{96 grams of O_{2}}$

<u><em>mass of Al₂O₃= 102 grams</em></u>

Finally, 102 grams of Al₂O₃ are formed when 48 grams of O₂ react.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

3 0

2 years ago