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aev [14]
3 years ago
15

The complete orbital notation diagram of an atom is shown. Five squares are shown aligned horizontally. Inside the first square

from the left is shown one upwards pointing arrow and one downwards pointing arrow. In the second square is another pair of upwards and downwards pointing arrow. Inside the third square is another pair of upwards and downwards pointing arrow. Inside the fourth square is another upwards and downwards pointing arrow. Inside the fifth square is an upwards pointing arrow. Based on the diagram, what values can be assigned to the angular momentum quantum number for the electrons in the atom? What information does this quantum number provide about the location of the electron?

Chemistry
1 answer:
Jlenok [28]3 years ago
6 0

Answer:

l = 0, 1, and 2; it is in a d orbital.  

Explanation:

1. Angular momentum quantum number

One square means l = 0.

Three squares mean l = 1.

Five squares mean l = 2.

If an atom contains electrons with l = 2, it must also have electrons with l = 0 and 1.

Thus, the electrons in the atom can be assigned the angular momentum quantum numbers l = 0, 1, and 2.

Those in a set of five squares all have l = 2.

2. Location of electron

The last electron is the lone electron in the fifth square. Since l = 2, the electron is in a d orbital.

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The given question is incomplete. The complete question is as follows.

Sodium sulfate is slowly added to a solution containing 0.0500 M Ca^{2+}(aq) and 0.0390 M Ag^{+}(aq). What will be the concentration of Ca^{2+}(aq) when Ag_{2}SO_{4}(s) begins to precipitate? What percentage of the Ca^{2+}(aq) can be separated from the Ag(aq) by selective precipitation?

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The given reaction is as follows.

      Ag_{2}SO_{4} \rightleftharpoons 2Ag^{+} + SO^{2-}_{4}

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When Ag_{2}SO_{4} precipitates then expression for K_{sp} will be as follows.

         K_{sp} = [Ag^{+}]^{2}[SO^{2-}_{4}]

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               \frac{0.00625}{0.05} \times 100

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                     100 - 12.5

                     = 87.5%

Thus, we can conclude that 87.5% will be the concentration of Ca^{2+}(aq) when Ag_{2}SO_{4}(s) begins to precipitate.

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