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aev [14]
3 years ago
15

The complete orbital notation diagram of an atom is shown. Five squares are shown aligned horizontally. Inside the first square

from the left is shown one upwards pointing arrow and one downwards pointing arrow. In the second square is another pair of upwards and downwards pointing arrow. Inside the third square is another pair of upwards and downwards pointing arrow. Inside the fourth square is another upwards and downwards pointing arrow. Inside the fifth square is an upwards pointing arrow. Based on the diagram, what values can be assigned to the angular momentum quantum number for the electrons in the atom? What information does this quantum number provide about the location of the electron?

Chemistry
1 answer:
Jlenok [28]3 years ago
6 0

Answer:

l = 0, 1, and 2; it is in a d orbital.  

Explanation:

1. Angular momentum quantum number

One square means l = 0.

Three squares mean l = 1.

Five squares mean l = 2.

If an atom contains electrons with l = 2, it must also have electrons with l = 0 and 1.

Thus, the electrons in the atom can be assigned the angular momentum quantum numbers l = 0, 1, and 2.

Those in a set of five squares all have l = 2.

2. Location of electron

The last electron is the lone electron in the fifth square. Since l = 2, the electron is in a d orbital.

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lbvjy [14]

0.0102 moles Na₂CO₃ = 1.08g of Na₂CO₃ is necessary  to reach stoichiometric quantities with cacl2.

<h3>Explanation:</h3>

Based on the reaction

CaCl₂ + Na₂CO₃ → 2NaCl + CaCO₃

1 mole of CaCl₂ reacts per mole of Na₂CO₃

we have to calculate how many moles of CaCl2•2H2O are present in 1.50 g

  • We must calculate the moles of CaCl2•2H2O using its molar mass (147.0146g/mol) in order to answer this issue.
  • These moles, which are equal to moles of CaCl2 and moles of Na2CO3, are required to obtain stoichiometric amounts.
  • Then, we must use the molar mass of Na2CO3 (105.99g/mol) to determine the mass:

<h3>Moles CaCl₂.2H₂O:</h3>

1.50g * (1mol / 147.0146g) = 0.0102 moles CaCl₂.2H₂O = 0.0102moles CaCl₂

Moles Na₂CO₃:

0.0102 moles Na₂CO₃

Mass Na₂CO₃:

0.0102 moles * (105.99g / mol) = 1.08g of Na₂CO₃ are present

Therefore, we can conclude that 0.0102 moles Na₂CO₃  is necessary.to reach stoichiometric quantities with cacl2.

To learn more about stoichiometric quantities visit:

<h3>brainly.com/question/28174111</h3>

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Spoiling is a chemical reaction because spoiled food has bad smell and taste and it changes colour too.

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