1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
siniylev [52]
2 years ago
10

1.52 moles of gas are at a pressure of 99.5kPa and a temperature of 298K. What is the volume of the gas

Chemistry
1 answer:
dangina [55]2 years ago
7 0

Answer:

5

Explanation:

answer my last question plz

You might be interested in
What is the balanced NET ionic equation for the reaction when aqueous Cs₃PO₄ and aqueous AgNO₃ are mixed in solution to form sol
rusak2 [61]

Answer:

PO_4^{3-}(aq)+3Ag^+(aq)\rightarrow Ag_3PO_4(s)

Explanation:

Hello!

In this case, since the net ionic equation of a chemical reaction shows up the ionic species that result from the simplification of the spectator ions, which are those at both reactants and products sides, we take into account that aqueous species ionize into ions whereas liquid, solid and gas species remain unionized. In such a way, for the reaction of cesium phosphate and silver nitrate we can write the complete molecular equation:

Cs_3PO_4(aq)+3AgNO_3(aq)\rightarrow Ag_3PO_4(s)+3CsNO_3(aq)

Whereas the three aqueous salts are ionized in order to write the following complete ionic equation:

3Cs^+(aq)+PO_4^{3-}(aq)+3Ag^+(aq)+3NO_3^-(aq)\rightarrow Ag_3PO_4(s)+3Cs^+(aq)+3NO_3^-(aq)

In such a way, since the cesium and nitrate ions are the spectator ions because of the aforementioned, the net ionic equation turns out:

PO_4^{3-}(aq)+3Ag^+(aq)\rightarrow Ag_3PO_4(s)

Best regards!

7 0
3 years ago
An element has an atomic number of 27. How many protons and electrons are in a neutral atom of the element
Sergeu [11.5K]

Answer:

27 and 32

Explanation:

3 0
2 years ago
Read 2 more answers
A group of students is investigating whether aluminum is a better thermal conductor than steel. The students take an aluminum wi
Mademuasel [1]

The students have conducted an experiment to check their hypothesis on the thermal conductivity of two metals; Aluminum and steel. The experimental observations have been noted, and the next step based on the scientific procedure is to analyze the data.

Analysis of data suggests that; since the length of wax after 10 min is lower in Al than steel, aluminum is a better thermal conductor.

Ans B) Analyze the data

7 0
3 years ago
Read 2 more answers
HELP PLEASE I WILL GIVE 100 PONTS
pochemuha

Answer:

boiling point

Explanation:

5 0
3 years ago
Read 2 more answers
When testing for hydrogen gas in the laboratory a glowing splint is inserted into the gas which results in a pop sound. What is
Advocard [28]
C. Exothermic reaction I guess
5 0
2 years ago
Other questions:
  • What are some physical properties in a water hat?
    13·2 answers
  • Determine the oxidation states of the elements in the compounds listed. None of the oxygen-containing compounds are peroxides or
    9·1 answer
  • Help on question 1b please? (image attached)
    13·1 answer
  • Argon, which comprises almost 1 percent of the atmosphere, is approximately 27 times more abundant than CO2 but does not contrib
    13·1 answer
  • 7. Phosphorus 32 ( 32), a radioactive isotope of phosphorus, has a half-life of 14.2 days. a. If the amount of radioactivity of
    8·1 answer
  • Describe the distribution of mass within an atom
    8·2 answers
  • Answer True or False for each of the following statements. (a) The carburization surface was maintained at slightly less than 0.
    13·1 answer
  • I NEED ANSWER ASAP Which of the following statements is true for a scientific theory? It is a well-tested hypothesis. It is veri
    10·2 answers
  • certain gas occupies 6.24L at pressure of 760 mm Hg.If the pressure is reduced to 60.0mm Hg,what would the new volume be?​
    14·1 answer
  • Within the visible spectrum, red light has
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!