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vagabundo [1.1K]
3 years ago
10

7. If the impact of the golf club on the ball in the previous question occurs over a time of 2 x 10 seconds, what

Physics
1 answer:
Kruka [31]3 years ago
4 0

Answer:

3.65 x mass

Explanation:

Given parameters:

Time  = 20s

Initial velocity  = 0m/s

Final velocity  = 73m/s

Unknown:

Force the ball experience  = ?

Solution:

To solve this problem, we apply the equation from newton's second law of motion:

    F  =  m \frac{v  - u}{t}  

m is the mass

v is the final velocity

u is the initial velocity

 t is the time taken

So;

  F  = m (\frac{73 - 0}{20} )  = 3.65 x mass

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Consider a 40,000 km steel pipe in the shape of a ring that fits snuggly all around the circumference of the Earth. We are heati
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The Height is  H = 70.02 m

Explanation:

We are given that the

                         Initial length is  = 40000\ Km = 40,000 *10^{3} m

from what we are told in the question the circumference of the circle is = 40,000 Km

  This means that the Radius would be :

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We are told that 1-meter bar of steel that increases its temperature by 1 degree C will expand 11*10^{-6} meters

Hence

       The final length would be

                            40000*10^3 *(T + \alpha  )

Where T is the change in  temperature  \alpha is the Coefficient of linear expansion for steel

  let L_{final} denote the final length

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        L_{final} =40000*10^{6} *[1+ 11*10^{-6}]

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As a pendulum swings, its potential energy changes to kinetic energy and kinetic energy changes into potential energy. At the top more potential energy is present.

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