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suter [353]
3 years ago
5

Calculate the pH of hydronium ions in a 0.000 01 M solution of the strong acid HI.

Physics
1 answer:
enyata [817]3 years ago
7 0
<h3>Answer:</h3>

pH = 5

<h3>Explanation:</h3>

<u>We are given;</u>

  • Concentration of a solution HI as 0.00001 M

We are required to calculate the pH of Hydronium ions.

  • When the acid dissociates in water to;

HI + H₂O → H₃O⁺(aq) + I⁻(aq)

  • Therefore;
  • The concentration of H₃O⁺ ions is 0.00001 M\
  • We need to know that pH = -log[H₃O⁺]

Therefore;

pH =-log 0.00001 M

     = 5

Thus, the pH of the hydronium ions is 5

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Higher mass protostars enter the main sequence: at the same rate, but at a higher luminosity and temperature. slower and at a lo
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Answer:

<em>faster and at a higher luminosity and temperature.</em>

Explanation:

A protostar looks like a star but its core is not yet hot enough for fusion to take place. The luminosity comes exclusively from the heating of the protostar as it contracts. Protostars are usually surrounded by dust, which blocks the light that they emit, so they are difficult to observe in the visible spectrum.

A protostar becomes a main sequence star when its core temperature exceeds 10 million K. This is the temperature needed for hydrogen fusion to operate efficiently.

Stars above about 200 solar masses (Higher mass) generate power so furiously that gravity cannot contain their internal pressure. These stars blow themselves apart and do not exist for long if at all. A protostar with less than 0.08 solar masses never reaches the 10 million K temperature needed for efficient hydrogen fusion. These result in “failed stars” called brown dwarfs which radiate mainly in the infrared and look deep red in color. They are very dim and difficult to detect, but there might be many of them, and in fact they might outnumber other stars in the universe.

That is why higher mass protostars enter the main sequence at a <em>faster and at a higher luminosity and temperature.</em>

8 0
3 years ago
two horses pull against a rope with forces of 100 newtons in opposite directions. this is an example of
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4 0
3 years ago
Read 2 more answers
A helicopter blade spins at exactly 110 revolutions per minute. Its tip is 4.50 m from the center of rotation. (a) Calculate th
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Answer:

(a). The average speed is 51.83 m/s.

(b). The average velocity over one revolution is zero.

Explanation:

Given that,

Angular velocity = 110 rev/m

Radius = 4.50 m

(a). We need to calculate the average speed

Using formula of average speed

v=r\omega

v = 4.50\times110\times\dfrac{2\pi}{60}

v=51.83\ m/s

(b). The average velocity over one revolution is zero because the net displacement is zero in one revolution.

Hence, (a). The average speed is 51.83 m/s.

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8 0
2 years ago
In this problem, you will practice applying this formula to several situations involving angular acceleration. In all of these s
riadik2000 [5.3K]

Answer:

Part a)

\alpha = \frac{2(m_1 - m_2)g}{(m_1 + m_2)L}

Part b)

\alpha = \frac{6(m1 - m_2)g}{3(m_1 + m_2)L + m_{bar}L}

Explanation:

As we know that the see saw bar is massless so here torque due to two masses is given as

\tau = I\alpha

here we will have

\tau = (m_1g - m_2g)(\frac{L}{2})

now we will have inertia of two masses given as

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now we have

I = (m_1 + m_2)\frac{L^2}{4}

now the angular acceleration is given as

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so we have

\alpha = \frac{2(m_1 - m_2)g}{(m_1 + m_2)L}

Part b)

Now if the rod is not massles then we will have total inertia given as

I = (m_1 + m_2)(\frac{L}{2})^2 + \frac{m_{bar}L^2}{12}

so we will have

I = (m_1 + m_2)\frac{L^2}{4} + \frac{m_{bar}L^2}{12}

now the acceleration is given as

\alpha = \frac{\tau}{I}

\alpha = \frac{6(m1 - m_2)g}{3(m_1 + m_2)L + m_{bar}L}

7 0
3 years ago
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