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3 years ago

Calculate the pH of hydronium ions in a 0.000 01 M solution of the strong acid HI.

Physics

1 answer:

enyata [817]3 years ago

7 0

<h3>Answer:</h3>

pH = 5

<h3>Explanation:</h3>

<u>We are given;</u>

Concentration of a solution HI as 0.00001 M

We are required to calculate the pH of Hydronium ions.

When the acid dissociates in water to;

HI + H₂O → H₃O⁺(aq) + I⁻(aq)

Therefore;

The concentration of H₃O⁺ ions is 0.00001 M\

We need to know that pH = -log[H₃O⁺]

Therefore;

pH =-log 0.00001 M

= 5

Thus, the pH of the hydronium ions is 5

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Now we will find the ratio of the Kinetic energies.

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Plugging the values of $\omega _f^2$ as $\omega _f^2 =(\frac{I_t}{I_t+I_r} \times \omega_i\ )^2$ from equation (i) in the ratios of the Kinetic energies.

⇒ $\frac{K_f}{K_i} =\frac{(I_t+I_r)\times \frac{(I_t)^2}{(I_t+I_r)^2} \times \omega_i^2}{I_t\times \omega_i^2} =\frac{(I_t)^2}{(I_t+I_r)}\times \frac{1}{I_t}=\frac{I_t}{I_t+I_r}$