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3 years ago

Someone tell me the slope please

Mathematics

2 answers:

sladkih [1.3K]3 years ago

4 0

Answer:

$\frac{0}{5}$ or zero.

Step-by-step explanation:

The pair on the left is (-4, -5). The pair on the right is (1, -5).

In order to find the slope, you must first subtract the y in the first pair by the y in the second pair. Then what ever answer you get will be your numerator. Then, subtract the x in the second pair by the x in the first pair and that will be your denominator. So, in this case, it would be $\frac{-5 - -5}{1 - -4}$ which equals $\frac{0}{5}$ . If a zero is the numerator, that means that the fraction is zero. If the zero had been on the bottom, then the answer would have been undefined.

In short the formula to find slope is: $y^{2}$ - $y^{1}$ over $x^{2}$ - $x^{1}$ .

liraira [26]3 years ago

3 0

M=0
The equation for slope is: (y2 - y1)/(x2 - x1)
The two points you have are (-4,-5) and (1,-5)

If I plug them in, I get: (-5 + 5)/(1 + 4) = 0/5

0 divided by any number is 0, so your slope is 0.

I hope this helps!

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a) $df=n-1=16-1=15$

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b) $df=n-1=8-1=7$

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Since is a one-side upper test the p value would be:

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So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

c) $df=n-1=26-1=25$

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Since is a one-side upper test the p value would be:

$p_v =P(t_{25}>-0.6)=0.723$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation

$\bar X$ represent the sample mean

$s$ represent the standard deviation for the sample

$n$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the true mean is higher than 20, the system of hypothesis would be:

Null hypothesis: $\mu \leq 20$

Alternative hypothesis: $\mu > 20$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

(a) n = 16, t = 3.3, a = 0.05, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=16-1=15$

The statistic calculated is given by t=3.3

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>3.3)=0.0024$

So since the p value is lower than the significance level $pv$ we reject the null hypothesis.

(b) n = 8, t = 1.8, a = 0.01, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=8-1=7$

The statistic calculated is given by t=1.8

Since is a one-side upper test the p value would be:

$p_v =P(t_{7}>1.8)=0.057$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

(c) n = 26,t = -0.6, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=26-1=25$

The statistic calculated is given by t=-0.6

Since is a one-side upper test the p value would be:

$p_v =P(t_{25}>-0.6)=0.723$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

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