The resistance of a 2 m long tungsten wire whose cross-sectional area of 0.15 mm² will be 0.74 ohm.
<h3>What is resistance?</h3>
Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.
ρ is the resistivity of tungsten = 5.6×10⁻⁸ (ohm m)
The relation of resistance with length and thickness is given by ;
![\rm R= \frac{\rho L}{A} \\\\ \rm R= \frac{5.6 \times 10^{-8}\times 2}{0.15 \times 10^{-6}} \\\\ R=0.74 \ ohm](https://tex.z-dn.net/?f=%5Crm%20R%3D%20%5Cfrac%7B%5Crho%20L%7D%7BA%7D%20%5C%5C%5C%5C%20%5Crm%20R%3D%20%5Cfrac%7B5.6%20%5Ctimes%2010%5E%7B-8%7D%5Ctimes%202%7D%7B0.15%20%5Ctimes%2010%5E%7B-6%7D%7D%20%5C%5C%5C%5C%20R%3D0.74%20%5C%20ohm)
Hence, the resistance of tungsten wire will be 0.74 ohm.
To learn more about the resistance, refer to the link;
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Here is your answer:
Therefore your answer is option B "30km."
Hope this helps!
Answer:
4 s
-24.5 m/s
Explanation:
y = y₀ + v₀ t + ½ at²
v = at + v₀
where y is the final position,
y₀ is the initial position,
v₀ is the initial velocity,
a is the acceleration,
and t is time.
Given:
y = 0 m
y₀ = 19.6 m
v₀ = 14.7 m/s
g = -9.8 m/s²
Find: t, v
Substitute values into the first equation and find t:
y = y₀ + v₀ t + ½ at²
0 = 19.6 + 14.7 t + ½ (-9.8) t²
0 = 19.6 + 14.7 t − 4.9 t²
0 = t² − 3 t − 4
0 = (t − 4) (t + 1)
t = -1 or 4
Since t must be positive, t = 4 seconds.
Now use the second equation to find v:
v = at + v₀
v = (-9.8) (4) + 14.7
v = -24.5
The mass of the football player is 250 kg.
<u>Explanation:</u>
Momentum is defined as the product of mass and velocity. So here the velocity (v) is given as 10 m/s and the momentum is given as 2500 kg m /s. So we can determine the mass (m) of the player by substituting the known terms in the formula of determining momentum as shown below.
![\text {Momentum}(p)=m \times v](https://tex.z-dn.net/?f=%5Ctext%20%7BMomentum%7D%28p%29%3Dm%20%5Ctimes%20v)
As we know the value of momentum and velocity, the mass can be found as,
![m=\frac{p}{v}=\frac{2500}{10}=250 \mathrm{kg}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7Bp%7D%7Bv%7D%3D%5Cfrac%7B2500%7D%7B10%7D%3D250%20%5Cmathrm%7Bkg%7D)
Thus, the mass of the football player is found to be 250 kg.
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