Question

A concert loudspeaker suspended high off the ground emits 26.0 W of sound power. A small microphone with a 1.00 cm2 area is 53.0 m from the speaker. Part A What is the sound intensity at the position of the microphone

Answer 1

Answer:

the sound intensity at the position of the microphone is 7.4 × 10⁻⁴ W/m²

Explanation:

Given the data in the question;

Sound power P = 26.0 W

Area of microphone A = 1.00 cm²

Radius r = 53.0 m

sound intensity at the position of the microphone = ?

Now, intensity at the position of the microphone can be determined using the following expression;

$I$ = P / 4πr²

We substitute

$I$ = 26.0 / ( 4 × π × (53.0 )² )

$I$ = 26.0 / ( 4 × π × 2809 )

$I$ = 26.0 / 35298.935

$I$ = 26.0 / ( 4 × π × (53.0 )² )

$I$ = 0.000736566

$I$ = 7.4 × 10⁻⁴ W/m²

Therefore, the sound intensity at the position of the microphone is 7.4 × 10⁻⁴ W/m²