Answer:
A. S0 = 1, S1 = 0, S2 = 0
lines need to send data for the fifth bit in an 8 bit system
Watts I believe is the answer
Answer with Explanation:
Assuming that the degree of consolidation is less than 60% the relation between time factor and the degree of consolidation is

Solving for 'U' we get

Since our assumption is correct thus we conclude that degree of consolidation is 50.46%
The consolidation at different level's is obtained from the attached graph corresponding to Tv = 0.2
i)
= 71% consolidation
ii)
= 45% consolidation
iii)
= 30% consolidation
Part b)
The degree of consolidation is given by

Thus a settlement of 50.46 centimeters has occurred
For time factor 0.7, U is given by

thus consolidation of 85.59 % has occured if time factor is 0.7
The degree of consolidation is given by

Answer:
a) The additional time required for the truck to stop is <u>8.5 seconds</u>
b) The additional distance traveled by the truck is <u>230.05 ft</u>
Explanation:
Since the acceleration is constant, the average speed is:
(final speed - initial speed) / 2 = 0.75 v0
Since travelling at this speed for 8.5 seconds causes the vehicle to travel 690 ft, we can solve for v0:
0.75v0 * 8.5 = 690
v0 = 108.24 ft/s
The speed after 8.5 seconds is: 108.24 / 2 = 54.12 ft/s
We can now use the following equation to solve for acceleration:


a = -6.367 m/s^2
Additional time taken to decelerate: 54.12/6.367 = 8.5 seconds
Total distance traveled:

0 - 108.24^2 = 2 * (-6.367) * s
solving for s we get total distance traveled = 920.05 ft
Additional Distance Traveled: 920.05 - 690 = 230.05 ft