Question

A cylindrical tank is required to contain a gage pressure 520 kPa . The tank is to be made of A516 grade 60 steel with a maximum allowable normal stress of 150 MPa . If the inner diameter of the tank is 2.6 m , what is the minimum thickness, t, of the wall? Express your answer with appropriate units to three significant figures.

Answer 1

Answer:

t= 4.5 mm

Explanation:

Given that

P = 520 KPa ( gauge)

Maximum allowable normal stress ,σ= 150

d= 2.6 m

Wall thickness = t

The normal stress for pressure vessel given as

$\sigma=\dfrac{Pd}{2t}$               ( hoop stress)

We always take maximum stress for safe design.

$\sigma=\dfrac{Pd}{2t}$

Now by putting the values

$150\times 1000=\dfrac{520\times 2.6}{2t}$

t= 4.5 mm

So the minimum thickness, t, of the wall is 4.5 mm