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mars1129 [50]
3 years ago
6

How many miles of glucose are in 19.1 g of glucose

Chemistry
1 answer:
geniusboy [140]3 years ago
7 0

Answer:

did you mean moles? If so, answer is down below.

Explanation:

there are 0.106 moles of glucose in 19.1 g of glucose.

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I WILL GIVE BRAINLIEST!!!!!
Alexxx [7]
                                    HNO₃ + H₂S → S + NO + H₂<span>O

Assign Oxidation Number:

                                L.H.S                               R.H.S
           N in HNO</span>₃  =  +5                                     +2  =  N in NO
               S in H₂S  =  -2                                       0  =  S in S

Write Half cell Reactions:
Reduction Reaction:
                                 
3e⁻  +   HNO₃   →   NO      -------(1)
Oxidation Reaction:
                                  H₂S   →   S  +  2e⁻             -------(2)

Multiply eq. 1 with 2 and eq. 2 with 3 to balance electrons. 

                                          6e⁻  +   2 HNO₃   →   2 NO
                                    
                                             3 H₂S   →   3 S  +  6e⁻
                                                                                  Cancel e⁻s,
                                 ______________________________
                               
                             2 HNO₃  +  3 H₂S   →   2 NO  +  3 S  +  H₂O

Balance Oxygen Atoms by multiplying H₂O with 4, Hydrogen atoms will automatically get balance.

                            2 HNO₃  +  3 H₂S   →   2 NO  +  3 S  +  4H₂O


                                
4 0
3 years ago
Which buffer would be better able to hold a steady pH on the addition of strong acid, buffer 1 or buffer 2? Explain. Buffer 1: a
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Answer:

Buffer 1.

Explanation:

Ammonia is a weak base. It acts like a Bronsted-Lowry Base when it reacts with hydrogen ions.

\rm NH_3\; (aq) + H^{+}\; (aq) \to {NH_4}^{+}\; (aq).

\rm NH_3 gains one hydrogen ion to produce the ammonium ion \rm {NH_4}^{+}. In other words, \rm {NH_4}^{+} is the conjugate acid of the weak base \rm NH_3.

Both buffer 1 and 2 include

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The ammonia \rm NH_3 in the solution will react with hydrogen ions as they are added to the solution:

\rm NH_3\; (aq) + H^{+}\; (aq) \to {NH_4}^{+}\; (aq).

There are more \rm NH_3 in the buffer 1 than in buffer 2. It will take more strong acid to react with the majority of \rm NH_3 in the solution. Conversely, the pH of buffer 1 will be more steady than that in buffer 2 when the same amount of acid has been added.

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I think its D

Explanation:

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