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mars1129 [50]
3 years ago
6

How many miles of glucose are in 19.1 g of glucose

Chemistry
1 answer:
geniusboy [140]3 years ago
7 0

Answer:

did you mean moles? If so, answer is down below.

Explanation:

there are 0.106 moles of glucose in 19.1 g of glucose.

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How many milliliters of 0.150 M NaOH are required to neutralize 85.0 mL of 0.300 M H2SO4 ? The balanced neutralization reaction
nekit [7.7K]

Answer : The volume of NaOH required to neutralize is, 340 mL

Explanation :

To calculate the volume of base (NaOH), we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=0.300M\\V_1=85.0mL\\n_2=1\\M_2=0.150M\\V_2=?

Putting values in above equation, we get:

2\times 0.300M\times 85.0mL=1\times 0.150M\times V_2\\\\V_2=340mL

Hence, the volume of NaOH required to neutralize is, 340 mL

4 0
3 years ago
Please answer asap need it by Wednesday morning
marta [7]

Answer:

1.7 PH

Explanation:

Ph= -log(0.02)= 1.698

6 0
3 years ago
Modern oil tankers weigh over a half-million tons and have lengths of up to one-fourth miles. Such massive ships require a dista
uranmaximum [27]

Answer:

Acceleration = (change in speed) / (time for the change)

Change in speed= (0 - 26 km/hr) = -26 km/hr

(-26 km/hr) x (1,000 m/km) x (1 hr / 3,600 sec) = -7.222 m/sec

Average acceleration = (-7.222 m/s) / (22 min x 60sec/min) = -0.00547 m/sec²

Average speed during the stopping maneuver =

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Explanation:

4 0
3 years ago
If the density of an ideal gas at stp if found to be 0.0902 g/l, what is its molar mass?
lisabon 2012 [21]
P=0.0902 g/l
v=22.4 l/mol   (stp)

M=vp

M=22.4 l/mol * 0.0902 g/l=2.020 g/mol

M=2.020 g/mol
4 0
3 years ago
Read 2 more answers
Consider this reaction: HCO3− + H2S → H2CO3 + HS− Which is the Bronsted-Lowry base? H2S HCO3- HS– H2CO3
german

Answer:

hco3

Explanation: bc i said so

3 0
3 years ago
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