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mars1129 [50]
3 years ago
6

How many miles of glucose are in 19.1 g of glucose

Chemistry
1 answer:
geniusboy [140]3 years ago
7 0

Answer:

did you mean moles? If so, answer is down below.

Explanation:

there are 0.106 moles of glucose in 19.1 g of glucose.

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3.5g of nitrogen combine with 2g of oxygen to produce an oxide of nitrogen
Elenna [48]

Answer:

5.5g

Explanation:

Id k I search it up

4 0
2 years ago
g Determine the value of the equilibrium constant for this reaction if an initial concentration of N2O4(g) of 0.040 mol/L is red
jeyben [28]

Answer:

Explanation:

N₂O₄(g) ⇄ 2 NO₂

N₂O₄ reacted = .04 - .0055 = .0345 mole

NO₂ formed = 2 x .0345 = .069 moles

equilibrium constant = [ NO₂ ] ² / [ N₂O₄]

= .069² / .0055

= 0.865 .

7 0
3 years ago
A vegetable farmer wants to increase his harvest which of the following conditions should the farmer consider
hichkok12 [17]

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D. all of the above

6 0
2 years ago
This gas can be formed if a hydrogen bomb is detonated.
Levart [38]

Answer:

Helium.

Explanation:

Hydrogen in the bomb is used in the process of detonation. A stream of tritium, an isotope of hydrogen is released and this fissionable material is very unstable thus it turns during the detonation to helium 3. This triggers a series of reactions that produce large amounts of heat to the surrounding environment causing destruction.

7 0
3 years ago
Aluminum metal and manganese (IV) oxide react to produce aluminum oxide and manganese metal. What mass of manganese (IV) oxide r
gayaneshka [121]

Answer: 1.77 kg of manganese (IV) oxide reacts to produce 1.12kg of manganese metal.

Explanation:

The balanced chemical equation is:

4Al+3MnO_2\rightarrow 2Al_2O_3+3Mn

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

moles of manganese = \frac{1.12\times 1000g}{55g/mol}=20.4mol

According to stoichiometry :

3 moles of Mn is produced by = 3 moles of MnO_2

Thus 20.4 moles of Mn is produced by =\frac{3}{3}\times 20.4=20.4moles  of MnO_2

Mass of MnO_2=moles\times {\text {Molar mass}}=20.4moles\times 86.9g/mol=1773g=1.773kg    (1kg=1000g)

Thus 1.77 kg of manganese (IV) oxide reacts to produce 1.12kg of manganese metal.

6 0
3 years ago
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