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3 years ago

A 20 N object is placed on a surface and starts to slide. What is the MOST likely reason the object begins to move?

Chemistry

1 answer:

ra1l [238]3 years ago

8 0

Answer:

Explanation:

If the object starts to slide it must be on a slope.

There are 2 forces acting on the object - gravity and the friction between the object and the surface.

If sliding starts then the forces must be unbalanced.

The force of gravity is greater than the friction.

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From the Henderson-Hasselbalch equation, explain how the ratio [Al/[HA] changes with changing pH

Kryger [21]

Answer:

The ratio [A-]/[HA] increase when the pH increase and the ratio decrease when the pH decrease.

Explanation:

Every weak acid or base is at equilibrium with its conjugate base or acid respectively when it is dissolved in water.

$HA + H_{2}O$ ⇄ $A^{-} + H_{3}O^{+}$

This equilibrium depends on the molecule and it acidic constant (Ka). The Henderson-Hasselbalch equation,

$pH = pKa + Log \frac{[A^{-}]}{[HA]}$

shows the dependency between the pH of the solution, the pKa and the concentration of the species. If the pH decreases the concentration of protons will increase and the ratio between A- and AH will decrease. Instead, if the pH increases the concentration of protons will decreases and the ratio between A- and AH will increase.

5 0

3 years ago

Density of 2.7 g/ml and volume of 35.6 ml what is the mass

Anettt [7]

The math is set up like

35.6 ml * 2.7 g/ 1 ml

which will leave you with

96.12 g

3 0

4 years ago

What is the diagram of 2CO2

Fynjy0 [20]

Answer:

hope i helped!

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7 0

3 years ago

ENERGY CANNOT BE CREATED<br> TRUE<br> False<br> Other:

Yuliya22 [10]

Answer:

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8 0

4 years ago

Read 2 more answers

The normal boiling point of a substance is defined to be the temperature at which the liquid phase of the substance is in equili

boyakko [2]

Answer:

ΔSv = 0.1075 KJ/mol.K

Explanation:

Binary solution:

∴ a: solvent

∴ b: solute

in equilibrium:

μ*(g) = μ(l) = μ* +RTLnXa....chemical potential (μ)

⇒ Ln (1 - Xb) = ΔG/RT

∴ ΔG = ΔHv - TΔSv

⇒ Ln(1 -Xb) = ΔHv/RT - ΔSv/R

∴ Xb → 0:

⇒ Ln(1) = ΔHv/RT - ΔSv/R

∴ T = T*b....normal boiling point

⇒ 0 = ΔHv/RT*b - ΔSv/R

⇒ ΔSv = (R)(ΔHv/RT*b)

⇒ ΔSv = ΔHv/T*b

∴ T*b = 80°C ≅ 353 K

⇒ ΔSv = (38 KJ/mol)/(353 K)

⇒ ΔSv = 0.1075 KJ/mol.K

5 0

3 years ago