Formula 1!!!!!!!!!!!!!!!!!!!!!!!!!!
X is girl, and y is boy, they are formed by fission.
Answer:
AsF3:C2CI6
4:3
1.3618 moles: 1.02135 moles(1.3618÷4×3)
C2CI6 is the limting reagent
So the number of moles for AsCI3 is 0.817 moles( number of moles of the limting reagant) ÷3 ×4 (according to ratio by balancing chemical equation)=1.09 moles(3 s.f.)
or
Balanced equation
4AsF3 + 3C2Cl6 → 4AsCl3 + 3C2Cl2F4
Use stoichiometry to calculate the moles of AsCl3 that can be produced by each reactant.
Multiply the moles of each reactant by the mole ratio between it and AsCl3 in the balanced equation, so that the moles of the reactant cancel, leaving moles of AsCl3.
Explanation:
Answer:
yes that is the octet rule true
Answer:
3.03 g
Solution:
Data Given:
Molarity = 0.50 mol.L⁻¹
M.Mass = 121.1 g.mol⁻¹
Volume = 50 mL = 0.05 L
Step 1: Calculate moles as,
Molarity = Moles ÷ Volume
Solving for Moles,
Moles = Molarity × Volume
Putting values,
Moles = 0.50 mol.L⁻¹ × 0.05 L
Moles = 0.025 mol
Step 2: Calculate Mass of Tris as,
Moles = Mass ÷ M.Mass
Solving for Mass,
Mass = Moles × M.Mass
Putting values,
Mass = 0.025 mol × 121.1 g.mol⁻¹
Mass = 3.03 g
