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2 years ago

Jeff wrote the following statement:

Physics

2 answers:

S_A_V [24]2 years ago

8 0

Answer:

i think its the second one

Explanation:

simply because hes living by that theory wveryday that because his dads a good athlete then hell be one too

Sedbober [7]2 years ago

6 0

Answer:

Sry, i just finished this quiz its the 2nd one

Explanation:

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A slice of bread contains about 100 kcal. If specific heat of a person were 1.00 kcal/kg·°C, by how many °C would the temperatur

almond37 [142]

Answer:

(c) 1.43°C

Explanation:

If the energy in the bread are converted to heat.

Then, The heat transferred from the bread to person = 100 kcal.

From specific heat capacity,

Q = cmΔT............................ equation 1

Where Q = quantity of heat, m = mass of the person, c = specific heat capacity of the person, Δ = increase in temperature.

Making ΔT the subject the equation 1,

ΔT = Q/cm........................ equation 2

Where Q = 100 kcal, c= 1.00 kcal/kg.°C, m = 70.0 kg

Substituting these values into equation 2,

ΔT = 100/(1×70)

ΔT = 100/70

ΔT = 1.428

ΔT ≈ 1.43°C

The increase in temperature of the body is = 1.43°C

The right option is (c) 1.43°C

5 0

3 years ago

The picture shows rays passing through an unknown lens.

NeX [460]

it id D because it is directed at the middle of the lens so it will be the same

7 0

3 years ago

Read 2 more answers

1. A 1000 kg equipment lift travels up a 200 m shaft in 45 seconds. Assuming the speed is constant, what is the

ANTONII [103]

Answer:

43,555 W

Explanation:

Since the speed is constant, this means that the force applied to lift the equipment is equal to the weight of the equipment. So we can write:

$F=mg$

where

m = 1000 kg is the mass

$g=9.8 m/s^2$ is the acceleration due to gravity

So,

$F=(1000)(9.8)=9800 N$

Then the work done in lifting the equipment is:

$W=Fd$

where

d = 200 m is the displacement of the equpment

Substituting,

$W=(9800)(200)=1.96\cdot 10^6 J$

Finally, the power used to lift the equipment is the ratio between the work done and time taken:

$P=\frac{W}{t}$

where

$W=1.96\cdot 10^6 J$

t = 45 s is the time taken

Solving,

$P=\frac{1.96\cdot 10^6}{45}=43,555 W$

8 0

3 years ago

A 2000 kg roller coaster is at the top of a loop with a radius of 24 m. If its speed is 18 m/s at this point, what force does it

levacccp [35]

Answer:

$46620\ \text{N}$

Explanation:

m = Mass of roller coaster = 2000 kg

r = Radius of loop = 24 m

v = Velocity of roller coaster = 18 m/s

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

Normal force at the point will be

$N-mg=\dfrac{mv^2}{r}\\\Rightarrow N=\dfrac{mv^2}{r}+mg\\\Rightarrow N=\dfrac{2000\times 18^2}{24}+2000\times 9.81\\\Rightarrow N=46620\ \text{N}$

The force exerted on the track is $46620\ \text{N}$ .

8 0

3 years ago

What is the insertion for the brachialis

Alona [7]

Coronoid process of the ulna

6 0

3 years ago