The characteristics of cimematica we can analyze the circular motion.
- Circular motion is the combination of perpendicular linear motions through the Pythagorean theorem.
Kinematics describes the motion of bodies, looking for relationships between position, velocity, and acceleration.
In a circular motion we can analyze it as an oscillatory motion on the x-axis and another on the y-axis, both with the same angular velocity.
x = Aₓ cos wt
y = A_y sin wt.
The resulting position can be found using the Pythagorean theorem.
R² = x² + y ²
R² = Aₓ² cos2 + 
sin wt
R² = 
if the two displacements are equal, the movement is circular and if they are different, the movement is elliptical.
Consequently, a movement in several dimensions can be analyzed as several movements, one in each dimension.
In conclusion using the characteristics of cimematica we can analyze the circular motion:
- Circular motion is the combination of linear motions through the Pythagorean theorem.
Learn more about circular motion here: brainly.com/question/2285236
Answer:
Explanation:
Usando la ley de Hook tenemos:
Solving it for k we have:
Usando la misma ecuación y sabiendo k tenemos:
Espero esto te ayude!
Answer:
2 N
Explanation:
From the question, it's given that
Mass m = 0.2 kg
Acceleration a = 10 m/s^2
The force a soccer goalie experience when stopping a ball will be equal to the force at which the ball is being kicked. This is
F = ma
Substitute all the parameters into the formula
F = 0.2 × 10
F = 2 Newton.
<u>Answer:</u>
Velocity of the dog relative to the road = 26.04 m/s 3.15⁰ north of east.
<u>Explanation:</u>
Let the east point towards positive X-axis and north point towards positive Y-axis.
Speed of truck = 25 m/s north = 25 j m/s
Speed of dog = 1.75 m/s at an angle of 35.0° east of north = (1.75 cos 35 i + 1.75 sin 35 j)m/s
= (1.43 i + 1.00 j) m/s
Velocity of the dog relative to the road = 25 j + 1.43 i + 1.00 j = 1.43 i + 26.00 j
Magnitude of velocity = 26.04 m/s
Angle from positive horizontal axis = 86.85⁰
So Velocity of the dog relative to the road = 26.04 m/s 86.85⁰ east of north = 26.04 m/s 3.15⁰ north of east.
I don’t know what’s up with chin man ??
