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3 years ago

13

An air craft heads. north at 400 km/hrs relative to the wind the air craft velocity is 300 km/hrs due north .find the velocity o

f the wind to the ground.

1 answer:

LUCKY_DIMON [66]3 years ago

8 0

Answer:

325

Explanation

seio na:

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12. A boy of mass 50 kg running 5m/s jumps on to a 20kg trolley

atroni [7]

Answer:

4 m/s

Explanation:

Momentum is conserved.

m₁ v₁ + m₂ v₂ = (m₁ + m₂) v

(50)(5) + (20)(1.5) = (50 + 20) v

v = 4

The final velocity is 4 m/s.

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3 years ago

Use complete sentences to explain how global wind patterns such as the polar easterlies in the southern hemisphere would be impa

Veseljchak [2.6K]

The impact would be great it would possibly freeze the work or melt the polar ice caps and flood the world to were we would invent technology light years away.

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3 years ago

Read 2 more answers

Which statement explains why you are thrown forward when the car you are riding in suddenly stops ?

ozzi

Answer:

You are are in motion as the car is driving ñ, and when it stops, your body continues to be in motion

Explanation:

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3 years ago

How much heat is absorbed by a 450g gold block as energy from the sun causes its temperature to change from 27°C to 32°C? (Speci

kotegsom [21]

Answer:

Q = 1057.5 [cal]

Explanation:

In order to solve this problem, we must use the following equation of thermal energy.

$Q=m*C_{p}*(T_{final}-T_{initial})$

where:

Q = heat energy [cal]

Cp = specific heat = 0.47 [cal/g*°C]

T_final = final temperature = 32 [°C]

T_initial = initial temperature = 27 [°C]

m = mass of the substance = 450 [g]

Now replacing:

$Q=450*0.47*(32-27)\\Q=1057.5[cal]$

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2 years ago

A ball is projected horizontally from the top of a bertical building 25.0m above the ground level with an initial velocity of 8.

kirill115 [55]

Answer:

Solution given:

height [H]=25m

initial velocity [u]=8.25m/s

g=9.8m/s

now;

a. How long is the ball in flight before striking the ground?

Time of flight =?

Now

Time of flight= $\sqrt{\frac{2H}{g}}$

substituting value

= $\sqrt{\frac{2*25}{9.8}}$
=2.26seconds

<h3><u>the ball is in flight before striking the ground for 2.26seconds</u>.</h3>

b. How far from the building does the ball strike the ground?

<u>H</u><u>o</u><u>r</u><u>i</u><u>z</u><u>o</u><u>n</u><u>t</u><u>a</u><u>l</u><u> </u>range=?

we have

Horizontal range=u* $\sqrt{\frac{2H}{g}}$

=8.25*2.26
=18.63m

<h3><u>The ball strikes 18.63m far from building</u>. </h3>

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2 years ago