Answer:
1 = Q = 7315 j
2 =Q = -21937.5 j
Explanation:
Given data:
Mass of water = 50 g
Initial temperature = 20°C
Final temperature = 55°C
Energy required to change the temperature = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of water is 4.18 j/g.°C.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 55°C - 20°C
ΔT = 35°C
Q = 50 g× 4.18 j/g.°C×35°C
Q = 7315 j
Q 2:
Given data:
Mass of metal = 100 g
Initial temperature = 1000°C
Final temperature = 25°C
Energy released = ?
Specific heat capacity = 0.225 j/g.°C
Solution:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 25°C - 1000°C
ΔT = -975°C
Now we will put the values in formula.
Q = 100 g × 0.225 j/g.°C × -975°C
Q = -21937.5 j
Negative sign show that energy is released.
Answer:
The correct option is A
Explanation:
Some amino acids, called glucogenic amino acids, when catabolized convert there carbon backbones to tricarboxylic acid (TCA) cycle intermediates. These intermediates can be subsequently metabolized into carbon dioxide and water with the release of ATP or the formation of glucose (known as gluconeogenesis.
<u>All amino acids (with the exception of leucine and lysine) are glucogenic and can thus generate the carbon backbones required for gluconeogenesis</u>. Thus, the correct option is a.
Answer:
Okay I will, Maritime tropical (mT) air masses are warm, moist, and usually unstable. Some maritime tropical air masses originate in the subtropical Pacific Ocean, where it is warm and air must travel a long distance over water. These rarely extend north or east of southern California.
got it
90.0 g of vanadium (V) oxygen sample has 1.50 x 10 24 oxygen atoms.
To determine the number of oxygen atoms in a vanadium oxide sample, the following steps must be made.
Step 1: Convert the mass of vanadium(V) oxide to mol of vanadium(V) oxide
mol vanadium(V) oxide = mass / molar mass
mol vanadium (V) oxide = 90.0 g / 181.88 g/mol
mol vanadium (V) oxide = 0.49483 mol
Step 2: Convert mol of vanadium (V) oxide to moles of oxygen using mole ratio
mol oxygen = mol vanadium (V) oxide * mole ratio O / mol V2O5
mol oxygen = 0.49483 mol * 5 mol O / mol V2O5
mol oxygen = 2.47416 mol O
Step 3: Convert to oxygen atoms using Avogadro's number
atoms oxygen = mol oxygen * 6.02214 x 10 23 atoms O /mol O
atoms oxygen = 2.47416 mol O * 6.02214 x 10 23 atoms O/mol O
atoms oxygen = 1.48997 x 10 24 atoms or 1.50 x 10 24 atoms O
To learn more about Avogadro's number, please refer to the link brainly.com/question/859564.
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