Answer : The volume of
produced will be, 0.8 liters.
Explanation : Given,
Volume of
= 1.2 L
At STP, 1 mole of substance contains 22.4 L volume of substance.
The given balanced chemical reaction is:

From the balanced chemical reaction we conclude that,
As,
volume of
produced
volume of 
So,
volume of
produced
volume of 
Therefore, the volume of
produced will be, 0.8 liters.
Answer:
.0027 M
Explanation:
We must calculate the threshold concentration of PO3−4 using Ksp and the given concentration of Ca2+:
Ca3(PO4)2(s)⇌3Ca2+(aq)+2PO3−4(aq)
Ksp=8.6×10−19=[Ca2+]3[PO3−4]2=(4.9×10−5M)3[PO3−4]2
[PO3−4]=0.0027 M
Answer:
0.24
Explanation:
We are given that
Rate constant for A=
Rate constant for B,k'=0.0750/s
We have to find the value of equilibrium constant for the reaction

Equilibrium constant, for k=
Using the formula

Hence, the value of the equilibrium constant for the reaction
at this temperature=0.24
Answer:
The answer to the question is option <u>D</u>