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Vikentia [17]
3 years ago
11

a metallic cube whose each side is 10 cm is subjected to a shearing force of 100 kg. The top force is displaced through 0.25 cm

with respect to the bottom. calculate the shearing stress strain and modulus​
Physics
1 answer:
baherus [9]3 years ago
8 0

Answer:

9.8×104Nm−2,0.025,3.92×106Nm−2

Solution :

Here, L=10cm=10×10−2m

F=100kgf=100×9.8N

ΔL=0.25cm=0.25×10−2m,

Shearing stress =FL2=100×9.8(10×10−2) Sheraing strain =ΔLL=0.25×10−210×10−2 = 0.025 Shear Modulus of elasticity, G=Shearing stressShearing strain=9.8×1040.025

=3.92×106Nm−2

Explanation:

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Answer:

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Explanation:

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v_{max}=\omega A............(1)

where \omega is the angular velocity and A is the amplitude.

The problem describes the oscillation of a loaded spring, and for a loaded spring the angular velocity is given by equation (2);

\omega=\sqrt{\frac{k}{m}}.................(2)

where k is the force constant of the spring and m is the loaded mass.

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\frac{v_{max}}{A}=\sqrt{\frac{k}{m}}.................(4)

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v_ {max }=1.92m/s\\A=0.21m\\k=223N/m

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