A volcanic eruption launches two rocks of different masses into the air. The first rock had a mass of 10 kilograms while the sec
2 answers:
Answer:
C. The amount of force applied to rock one was half the amount of force applied to rock two during the eruption.
Explanation:
A force is an agent which changes the state of an object well applied to it. Second Newton's law of motion state's that;
F = ma
where F is the force, m is the mass of the object and a is the acceleration of the object.
In the given question,
Mass of first rock = 10 kilograms
Mass of the second rock = 20 kilograms
Acceleration of the two rocks = 600 m/
Thus,
Force on the first rock = ma
= 10 x 600
= 6000 N
Force on the second rock = 20 x 600
= 12000 N
Therefore, it can be observed that the amount of force applied to rock one was half the amount of force applied to rock two during the eruption.
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Answer:
Kinetic energy of the projectile at the vertex of the trajectory: .
Work done when firing this projectile: .
Explanation:
Since the drag on this projectile is negligible, the horizontal velocity of this projectile would stay the same (at
) throughout the flight.
The vertical velocity of this projectile would be
at the vertex (highest point) of its trajectory. (Otherwise, if
, this projectile would continue moving up and reach an even higher point. If
, the projectile would be moving downwards, meaning that its previous location was higher than the current one.)
Overall, the velocity of this projectile would be when it is at the top of the trajectory. The kinetic energy
of this projectile (mass
) at the vertex of its trajectory would be:
.
Apply the Pythagorean Theorem to find the initial speed of this projectile:
.
Hence, the initial kinetic energy of this projectile would be:
.
All that energy was from the work done in launching this projectile. Hence, the (useful) work done in launching this projectile would be .