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charle [14.2K]
3 years ago
8

Round your answers to one decimal place. This parallel circuit has two resistors at 15 and 40 ohms. What is the total resistance

? Ω If there is a 12 V battery in the circuit, what would the approximate current be? A
Physics
2 answers:
Dmitriy789 [7]3 years ago
7 0

Answer:

10.9 ohms .

 1.1 Amperes  

Explanation:

goldenfox [79]3 years ago
4 0
-- With two resistors in parallel, the total effective resistance is
the reciprocal of  (1/R₁ + 1/R₂).

1/R₁ + 1/R₂  = 1/15 + 1/40

= 8/120 + 3/120

= 11/120

So the total effective resistance is 120/11 = 10.9 ohms .

Current = (voltage) / (resistance)

= 12 / (120/11)

= (12 · 11) / 120

= 132/120  =  1.1 Amperes  
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Answer:

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Explanation:

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now the displacement of the gardner along the floor is

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3 years ago
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Anna11 [10]

Answer:

8.1\:\mathrm{Ns}

Explanation:

The impulse-momentum theorem gives the impulse on an object to be equal to the change in momentum of that object. Since mass is maintained, the change in momentum of the basketball is:

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Since the basketball is changing direction, its total change in velocity is:

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Therefore, the basketball's change in momentum is:

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3 years ago
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Answer: The size of the whale can be estimated by using echo Sounder or Sonar

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The sonar is able to receive the signals from the whales and the succesive echoes that follows when placed in a strategic position in the water in the path of the whale .

The sonar has a traducers which has both a transmitter and a receiver,so it receives pulses from the whale and transmit back same echo back to the whale and to the bottom of the sea.

Using the speed of sound underwater and time taken for succesive echoes of pulses ,it can calculate with the precision the location of the whale while the image of the whale is also capture by the traducers to determine the size.

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3 years ago
A helium–neon laser emits a beam of circular cross section with a radius r and a power P.?. (a) Find the maximum electric field
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there is a relation between intensity of light beam and the magnitude of electric field.<span>I=(1/2)c<span>ϵo</span>n<span>E2</span>=P/π<span>r2</span></span> <span><span>E2</span>=2P/c<span>ϵo</span>nπ<span>r2</span></span> E= magnitude of electric field n= refractive index of medium <span><span>μo</span><span>ϵ0</span>=1/<span>c2
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