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iragen [17]
3 years ago
15

How do the sun and moon work together to create a neap tide?

Physics
1 answer:
slega [8]3 years ago
6 0

Answer:

<em>Neap</em><em> </em><em>tide</em><em>,</em><em> </em><em>which</em><em> </em><em>also</em><em> </em><em>occour</em><em> </em><em>twice</em><em> </em><em>a</em><em> </em><em>month</em><em>.</em><em> </em><em>I</em><em>t</em><em> </em><em>h</em><em>appens</em><em> </em><em>when</em><em> </em><em>sun</em><em> </em><em>and</em><em> </em><em>moon</em><em> </em><em>are</em><em> </em><em>right</em><em> </em><em>angle</em><em> </em><em>to</em><em> </em><em>each</em><em> </em><em>other</em><em>.</em>

Explanation:

<em>I</em><em>n</em><em> </em><em>b</em><em>o</em><em>t</em><em>h</em><em> </em><em>cases</em><em>,</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>gravitational</em><em> </em><em>p</em><em>u</em><em>l</em><em>l</em><em> </em><em>o</em><em>f</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>s</em><em>u</em><em>n</em><em> </em><em>i</em><em>s</em><em> </em><em>“</em><em>a</em><em>d</em><em>d</em><em>e</em><em>d</em><em>”</em><em>t</em><em>o</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>g</em><em>r</em><em>a</em><em>v</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em>a</em><em>l</em><em> </em><em>p</em><em>u</em><em>l</em><em>l</em><em> </em><em>o</em><em>f</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>m</em><em>o</em><em>o</em><em>n</em><em> </em><em>o</em><em>n</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>Earth</em><em>.</em>

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A bucket that has a mass of 20 kg when filled with sand needs to be lifted to the top of a 15 meter tall building. You have a ro
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Answer:

work done lifting the bucket (sand and rope) to the top of the building,

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Explanation:

in this question we have given

mass of bucket=20kg

mass of rope=.2\frac{kg}{m}

height of building= 15 meter

We have to find the work done lifting the bucket (sand and rope) to the building =work done in lifting the rope + work done in lifting the sand

work done in lifting the rope is given as,W_{1}=Force \times displacement

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work done in lifting the sand is given as,W_{2}=Force \times displacement

W_{2}=\int\limits^{15}_0 F \, dx.................(2)

Here,

F=mx+c

here,

c=20-18

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m=\frac{20-18}{15-0}

m=.133

Therefore,

F=.133x+2

Put value of F in equation 2

W_{2}=\int\limits^{15}_0 (.133x+2) \, dx

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