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iragen [17]
2 years ago
15

How do the sun and moon work together to create a neap tide?

Physics
1 answer:
slega [8]2 years ago
6 0

Answer:

<em>Neap</em><em> </em><em>tide</em><em>,</em><em> </em><em>which</em><em> </em><em>also</em><em> </em><em>occour</em><em> </em><em>twice</em><em> </em><em>a</em><em> </em><em>month</em><em>.</em><em> </em><em>I</em><em>t</em><em> </em><em>h</em><em>appens</em><em> </em><em>when</em><em> </em><em>sun</em><em> </em><em>and</em><em> </em><em>moon</em><em> </em><em>are</em><em> </em><em>right</em><em> </em><em>angle</em><em> </em><em>to</em><em> </em><em>each</em><em> </em><em>other</em><em>.</em>

Explanation:

<em>I</em><em>n</em><em> </em><em>b</em><em>o</em><em>t</em><em>h</em><em> </em><em>cases</em><em>,</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>gravitational</em><em> </em><em>p</em><em>u</em><em>l</em><em>l</em><em> </em><em>o</em><em>f</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>s</em><em>u</em><em>n</em><em> </em><em>i</em><em>s</em><em> </em><em>“</em><em>a</em><em>d</em><em>d</em><em>e</em><em>d</em><em>”</em><em>t</em><em>o</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>g</em><em>r</em><em>a</em><em>v</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em>a</em><em>l</em><em> </em><em>p</em><em>u</em><em>l</em><em>l</em><em> </em><em>o</em><em>f</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>m</em><em>o</em><em>o</em><em>n</em><em> </em><em>o</em><em>n</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>Earth</em><em>.</em>

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The formula that can be used to obtain a convergent series is given by;

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3 years ago
A child slides down a snow‑covered slope on a sled. At the top of the slope, her mother gives her a push to start her off with a
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Answer:

θ = 13.16 °

Explanation:

Lets take mass of child = m

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Final velocity ,v=3.7 m/s

d= 22.5 m

The force due to gravity along the incline plane = m g sinθ

The friction force = (m g)/5

Now from work power energy

We know that

work done by all forces = change in kinetic energy

( m g sinθ - (m g)/5 ) d = 1/2 m v² - 1/2 m u²

(2  g sinθ - ( 2 g)/5 ) d = v² -  u²

take g = 10 m/s²

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5 0
2 years ago
A parallel-plate capacitor has square plates that are 8.00cm on each side and 4.20mm apart. The space between the plates is comp
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Answer:

U=1.29\times 10^{-7}\ J

Explanation:

Given that

a= 8 cm (square)

A= a ² = 64 cm²

d= 4.2 mm

d₁= 2.1 mm  ,K₁= 4.7

d₂=2.1 mm  , K₂=2.6

We know that capacitance given as

C_1=\dfrac{K_1\varepsilon _oA}{d_1}

C_1=\dfrac{4.7\times 8.85\times 10^{-12}\times 64\times 10^{-4}}{2.1\times 10^{-3}}

C_1=1.26\times 10^{-10}\ F

C_2=\dfrac{K_2\varepsilon _oA}{d_2}

C_2=\dfrac{2.6\times 8.85\times 10^{-12}\times 64\times 10^{-4}}{2.1\times 10^{-3}}

C_2=0.701\times 10^{-10}\ F

Net capacitance

C=\dfrac{C_1C_2}{C_1+C_2}

C=\dfrac{1.26\times 10^{-10}\times 0.701\times 10^{-10}}{1.26\times 10^{-10}+0.701\times 10^{-10}}\ F

C=4.5\times 10^{-11}\ F

We know that stored energy given as

U=\dfrac{CV^2}{2}

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U=\dfrac{4.5\times 10^{-11}\times 76^2}{2}\ J

U=1.29\times 10^{-7}\ J

3 0
2 years ago
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