To determine the time it takes to completely vaporize the given amount of water, we first determine the total heat that is being absorbed from the process. To do this, we need information on the latent heat of vaporization of water. This heat is being absorbed by the process of phase change without any change in the temperature of the system. For water, it is equal to 40.8 kJ / mol.
Total heat = 40.8 kJ / mol ( 1.50 mol ) = 61.2 kJ of heat is to be absorbed
Given the constant rate of 19.0 J/s supply of energy to the system, we determine the time as follows:
Time = 61.2 kJ ( 1000 J / 1 kJ ) / 19.0 J/s = 3221.05 s
Answer:
There will not be any ejection of photoelectrons
Explanation:
Energy of the photon= hc/λ
Where;
h= Plank's constant
c= speed of light
λ= wavelength of the incident photon
E= 6.6×10^-34 × 3 ×10^8/488 × 10^-9
E= 4.1 ×10^-19 J
Work function of the metal (Wo)= 2.9 eV × 1.6 × 10^-19 = 4.64 × 10^-19 J
There can only be ejected photoelectrons when E>Wo but in this case, E<Wo hence there will not be any ejection of photoelectrons.
Answer:
2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O.
Explanation:
- To balance a chemical reaction, we apply the law of conversation of mass, states that the no. of atoms in both sides of the reactants and products is the same.
So, the balanced equation of combustion of butane is:
<em>2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O.</em>
- <em>It is clear that 2.0 moles of butane is burned in 13.0 moles of oxygen to produce 8.0 moles of CO₂ and 10.0 moles of H₂O.</em>
Answer:
The direction of the field is taken to be the direction of the force it would exert on a positive test charge. The electric field is radially outward from a positive charge and radially in toward a negative point charge.
Explanation:
