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2 years ago

Which of the following is NOT an event in track and field?

Physics

2 answers:

ad-work [718]2 years ago

7 0

Answer:

Explanation:

Dressage is a horse racing sport.

Ugo [173]2 years ago

3 0

Dressage. It’s an event in horseback riding.

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What types of cuts do jig saw sanders make?

LuckyWell [14K]

The jigsaw can be used to make both straight and curved cuts in a wide variety of materials, including wood, particleboard, plywood, plastic, metal, even ceramic tile. There is also way more than those, but those are just the basics or common things. Hope this helps!

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3 years ago

Read 2 more answers

A white dwarf is:______.

bija089 [108]

Answer:

the exposed core of a dead star, supported by electron degeneracy pressure.

Explanation:

A white dwarf is a low luminosity exposed core of a dead star having mass comparable to the sun but volume comparable to the earth . So its density is very high . These stars have lost the capacity to generate energy through the process of fusion . Due to high gravitational energy , it goes on shrinking but ultimately balanced by electron degeneracy pressure. It is not a main sequence star as it has lost the power of fusion .

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3 years ago

PLEASE HELP Scientists have observed that the average sunspots have increased in the last 50 years. Which of these statements be

Serga [27]

Answer:

option c is correct, earth temp increase

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3 years ago

A bowling ball of mass 5 kg rolls down a slick ramp 20 meters long at a 30 degree angle to the horizontal. What is the work done

Elena-2011 [213]

Answer:

The work done by gravity during the roll is 490.6 J

Explanation:

The work (W) is:

$W = F*d$

<em>Where</em>:

F: is the force

d: is the displacement = 20 m

The force is equal to the weight (W) in the x component:

$F = W_{x} = mgsin(\theta)$

<em>Where:</em>

m: is the mass of the bowling ball = 5 kg

g: is the gravity = 9.81 m/s²

θ: is the degree angle to the horizontal = 30°

$F = mgsin(\theta) = 5 kg*9.81 m/s^{2}*sin(30) = 24.53 N$

Now, we can find the work:

$W = F*d = 24.53 N*20 m = 490.6 J$

Therefore, the work done by gravity during the roll is 490.6 J.

I hope it helps you!

6 0

3 years ago

If the crate shown here is moving at a constant speed in a straight line and the force applied is 310 N, what is the magnitude o

larisa86 [58]

Answer:

$f_k = 310N$

the answer is A.

Explanation:

Using the laws of newton:

∑F = ma

where ∑F is the sumatory of forces acting in the system, m the mass and a the acelertion of the system.

Then, if the block is moving with constant velocity, its aceleration is equal to 0, so:

∑F = m(0)

∑F = 0

It means that:

F - $f_k$ = 0

where F is the force applied and $f_k$ is the friction force. Replacing the value of F, we get:

310N - $f_k$ = 0

Finally, solving for $f_k$ :

$f_k = 310N$

8 0

3 years ago