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monitta
2 years ago
6

Which of the following is NOT an event in track and field?

Physics
2 answers:
ad-work [718]2 years ago
7 0

Answer:

B

Explanation:

Dressage is a horse racing sport.

Ugo [173]2 years ago
3 0
Dressage. It’s an event in horseback riding.
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A 150 g egg is dropped from 3.0 meters. The egg is
Lynna [10]

<u><em>Answer:</em></u>

<u><em> </em></u>

<u><em>9.2 N, with significant figure rounding (2 s.f.) </em></u>

<u><em></em></u>

<u><em>Explanation:</em></u>

<u><em>This problem can be solved using momentum. The following equation relates momentum (mass & velocity) with force and time:</em></u>

<u><em></em></u>

<u><em>Note that  where v is the final velocity and v₀ is the initial velocity. Δv just means change in velocity.</em></u>

<u><em></em></u>

<u><em>Mass of the egg is 150 g, but we need to convert to kilograms if we want to use Newtons as a unit. 150 g is equal to 0.15 kg. since 1000 g = 1kg. </em></u>

<u><em>m = 0.15 kg</em></u>

<u><em></em></u>

<u><em>The dropped from 3.0 meters is irrelevant as the question tells us the initial velocity of the egg: 4.4 m/s before it hits the ground.</em></u>

<u><em>v₀ = 4.4 m/s [down]</em></u>

<u><em></em></u>

<u><em>When it comes to a stop, the egg will have a velocity of 0.</em></u>

<u><em>v = 0 m/s</em></u>

<u><em></em></u>

<u><em>The time it takes for the egg to stop is 0.072 seconds.</em></u>

<u><em>Δt = 0.072 s</em></u>

<u><em></em></u>

<u><em>Therefore, if down is positive, then</em></u>

<u><em></em></u>

<u><em>   </em></u>

<u><em></em></u>

<u><em>We round to two significant figures since every quantity has two sig. figs.</em></u>

<u><em>We only care about the magnitude, not direction. The answer is 9.2 N.</em></u>

<u><em>Unlimited, ad-free access to all of the questions with Brainly Plus</em></u>

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<u><em>5.0</em></u>

5 0
3 years ago
A 60-kg runner raises his center of mass approximately 0.5 m with each step. Although his leg muscles act as a spring, recapturi
Darina [25.2K]

Answer: P = 36.75W

The additional power needed to account for the loss is 36.75W.

Explanation:

Given;

Mass of the runner m= 60 kg

Height of the centre of gravity h= 0.5m

Acceleration due to gravity g= 9.8m/s

The potential energy of the body for each step is;

P.E = mgh

P.E = 60 × 9.8 × 0.5

PE = 294J

Since the average loss per compression on the leg is 10%.

Energy loss = 10% (P.E)

E = 10% of 294J

E = 29.4J

To calculate the runner's additional power

given that time per stride is = 0.8s

Power P = Energy/time

P = E/t

P = 29.4J/0.8s

P = 36.75W

5 0
3 years ago
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