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lyudmila [28]
3 years ago
11

The tangential acceleration of a cart moving at a constant speed in a horizontal circle is:

Physics
1 answer:
qaws [65]3 years ago
7 0

Answer:

a=0                                  ∵ \alpha=0\ rad.s^{-1}

Explanation:

The tangential acceleration of a cart moving at a constant speed in a circle is:

The angular velocity is constant when the circular speed is constant.

We know that the (instantaneous) tangential velocity of such object is given by:

v=r.\omega

Now for angular acceleration we have a constant angular speed:

\alpha=0\ rad.s^{-1}

And angular acceleration is related to tangential acceleration as:

a=r.\alpha

\Rightarrow a=0

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Answer:

a. The student's mistake was that the student did not swing the pendulum and start the watch at the same time.

b. 1.2 s per swing.

c. The likely effect of her reaction time is that they will should subtract two seconds off the time.

Explanation:

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2 years ago
Which item is an example of a primary source? A. An academic paper analyzing John F. Kennedy's presidency B. A transcript of a p
Viktor [21]

A transcript of a presidential speech (APEX Class ;)

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3 years ago
The two particles are both moving to the right. Particle 1 catches up with particle 2 and collides with it. The particles stick
Irina18 [472]

Answer:

See bolded below.

Explanation:

Consider the " Before " and " After. " " Before, " this particle 1 was trying to catch up with this particle 2, and " after " particle one had collided with particle two. Take a look at the attachment below for a more detailed examination.

Here is how this will play out. Particle 1, with great velocity, will hit particle 2, which would mean that Particle 2 has less velocity than Particle 1. Now after the collision, energy is transferred to Particle 2, and while Particle 1 has now stopped in it's tracks, Particle 2 - with more energy than before - will continue as long as it has to before friction eventually brings it to a stop.

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From this we can conclude that Vf, from the picture below, must have less energy than V1, but more energy than V2 - and vice versa.

8 0
3 years ago
Tyson Gay's best time to run 100.0 meters was 9.69 seconds. What was his average speed during this run, in miles per hour? (3.28
FinnZ [79.3K]

Answer:

23.086 mile/h

Explanation:

Given,

Distance Tyson Gay run = 100 m

time of run, t = 9.69 s

average speed of the in mph = ?

Speed of the Gay = \dfrac{distance}{time}

v = \dfrac{100}{9.69}

     v = 10.32 m/s

1 m = 3.281 ft

10.32 m = 33.86 ft

1 mile = 5280 ft

1 ft = 1.8939 x 10⁻⁴ mile

33.86 ft/s = 6.413 x 10⁻³ miles/s

Speed of Tyson in mile/hr = 6.413 x 10⁻³ x 3600

                                           = 23.086 mile/h

Hence, speed of Tyson Gay's in mile/ hr is equal to 23.086 mph.

4 0
2 years ago
Read 2 more answers
Which changes will decrease the electric force between two positively charged objects? Check all that apply.
zaharov [31]

Answer:

Moving them farther apart

Explanation:

The electric field between the two charges Q and q separated by a distance r is given by

E = \frac{K\times Q\times q}{r^{2}}

It shows that the electric field is inversely proportional to the square of the distance between two charges.

So, as the distance between two charges increases, the electric filed between the two charges decreases.

8 0
3 years ago
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