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Mice21 [21]
3 years ago
5

12. Why do you think afternoons are much warmer than the mornings or evenings? ​

Physics
1 answer:
Darya [45]3 years ago
6 0

Answer:

Afternoons are much warmer than the mornings or evenings is explained below in complete detail.

Explanation:

Because in the afternoon the sun is on the head and the beams of sunshine arrive straight to the earth so we exhibit warmer and in daylight and evening the sun is sparse to the earth so we observe colder than an afternoon. However, in the evening, when the sun is weak, I don't sense or experienced loads of heat and sunburn on body parts that are viewing the sun directly.

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Suppose a door is 1 meter wide. Calculate the difference in the amount torque exerted on the door when someone pushes with a con
Yanka [14]

Answer:

Δτ = 50 N.m

Explanation:

The torque applied on an object is given by the product of the force applied on it and the perpendicular distance between the force and the axis of rotation of the object. That is:

τ = F r

where,

τ = Torque applied on the object

F = Force applied on it

r = distance from axis of rotation

<u>FOR HANDLE SIDE OF DOOR</u>:

τ₁ = F r₁

where,

τ₁ = Torque applied on the object = ?

F = Force applied on it = 100 N

r₁ = distance from axis of rotation = 1 m

Therefore,

τ₁ = (100 N)(1 m)

τ₁ = 100 N.m

<u></u>

<u>FOR MIDDLE OF DOOR</u>:

τ₂ = F r₂

where,

τ₂ = Torque applied on the object = ?

F = Force applied on it = 100 N

r₂ = distance from axis of rotation = 1 m/2 = 0.5 m

Therefore,

τ₂ = (100 N)(0.5 m)

τ₂ = 50 N.m

Now, the difference between the amount of torque in both cases is:

Δτ = τ₁ - τ₂

Δτ = 100 N.m - 50 N.m

<u>Δτ = 50 N.m</u>

6 0
3 years ago
During radioactive decay, ___ energy was transformed to ____
Afina-wow [57]

Answer:

Potential energy is transfer to kinetic energy,

If radio active substance is decayed.

6 0
3 years ago
What is the gauge pressure in Pascals inside a honey droplet of a 0.1 cm diameter? Assume that air is surrounding this droplet a
Vikki [24]

Answer:

The gauge pressure in Pascals inside a honey droplet is 416 Pa

Explanation:

Given;

diameter of the honey droplet, D = 0.1 cm

radius of the honey droplet, R = 0.05 cm = 0.0005 m

surface tension of honey, γ = 0.052 N/m

Apply Laplace's law for a spherical membrane with two surfaces

Gauge pressure =  P₁ - P₀ = 2 (2γ / r)

Where;

P₀ is the atmospheric pressure

Gauge pressure = 4γ / r

Gauge pressure = 4 (0.052) / (0.0005)

Gauge pressure = 416 Pa

Therefore, the gauge pressure in Pascals inside a honey droplet is 416 Pa

5 0
4 years ago
The earth suddenly and enexpectedly loses all gravity. What would happen if gravity disappeared
belka [17]

Answer:

everything will be floating

Explanation:

there'll be nothing keeping us on the ground

7 0
3 years ago
Do number 7 show work
Harrizon [31]

Kinetic energy of any object = (1/2) (object's mass) (object's speed)²

Arrow's kinetic energy = (1/2) (0.217 kg) (100 m/s)² = 1,085 Joules

Pumpkin's kinetic energy = (1/2) (3.75 kg) (7.25 m/s)² = 98.5 Joules

== 1,085 Joules is more than 98.5 Joules.

==> <em>The arrow</em> has more kinetic energy than the pumpkin has.

7 0
3 years ago
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