The answer is B) They do NOT require a medium to travel.
Answer:
The acceleration of the cart is 1.0 m\s^2 in the negative direction.
Explanation:
Using the equation of motion:
Vf^2 = Vi^2 + 2*a*x
2*a*x = Vf^2 - Vi^2
a = (Vf^2 - Vi^2)/ 2*x
Where Vf is the final velocity of the cart, Vi is the initial velocity of the cart, a the acceleration of the cart and x the displacement of the cart.
Let x = Xf -Xi
Where Xf is the final position of the cart and Xi the initial position of the cart.
x = 12.5 - 0
x = 12.5
The cart comes to a stop before changing direction
Vf = 0 m/s
a = (0^2 - 5^2)/ 2*12.5
a = - 1 m/s^2
The cart is decelerating
Therefore the acceleration of the cart is 1.0 m\s^2 in the negative direction.
Answer:
the choice of a glider to hanging mass is a ratio of 20.2
Explanation:
The Newton´s second law for glider is:
Fnet=Ma
T=Ma
The Newton´s second law for hanging mass is:
Fnet=ma
mag-T=ma
Replacing:
mag-Ma=ma (eq. 1)
Clearing a:
a=(mg)/(m+M)
The expression for motion is:
Clearing a:
Replacing values:
From eq. 1:
M/m=20.2
Answer:
The answer is C she didn't mark C so its your best best of trying.Good Luck!
