Answer:
I will study about it and tell u....okk
Answer:
The average induced emf in the coil is 0.0286 V
Explanation:
Given;
diameter of the wire, d = 11.2 cm = 0.112 m
initial magnetic field, B₁ = 0.53 T
final magnetic field, B₂ = 0.24 T
time of change in magnetic field, t = 0.1 s
The induced emf in the coil is calculated as;
E = A(dB)/dt
where;
A is area of the coil = πr²
r is the radius of the wire coil = 0.112m / 2 = 0.056 m
A = π(0.056)²
A = 0.00985 m²
E = -0.00985(B₂-B₁)/t
E = 0.00985(B₁-B₂)/t
E = 0.00985(0.53 - 0.24)/0.1
E = 0.00985 (0.29)/ 0.1
E = 0.0286 V
Therefore, the average induced emf in the coil is 0.0286 V
Answer:
Speed of the runner during video interval is 6.49 m/s
Explanation:
According to the problem,
Number of frames recorded by camera in 1 second = 50
Time takes by camera to record 1 frame = (1/50) s
Time taken by camera to record 77 frames, t = s
Distance covered by the runner during the video recording, d = 10 m
Speed, v =
Substitute the values of d and t in the above equation.
v =
v = 6.49 m/s
Answer:
<h2>2000 W</h2>
Explanation:
The power of the crane can be found by using the formula
w is the workdone
t is the time taken
From the question we have
We have the final answer as
<h3>2000 W</h3>
Hope this helps you