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netineya [11]
3 years ago
11

An early planetary model of the hydrogen atom consisted of a 1.67 X 10-27 kg proton in the nucleus and a 9.11 X 10-31 kg electro

n in orbit around it at a distance of 5.0 X 10-11 m. In this model, what is the gravitational force between a proton and an electron?
Physics
1 answer:
lyudmila [28]3 years ago
3 0

Answer:

The gravitational force between proton and an electron is 4.06 \times 10^{-47} N

Explanation:

Given:

Mass of proton m_{1} = 1.67 \times 10^{-27} kg

Mass of electron m_{2} = 9.11 \times 10^{-31} kg

Separation between electron and proton r = 5 \times 10^{-11} m

According to the gravitational law,

   F = \frac{Gm_{1} m_{2}  }{r^{2} }

Where G = 6.674 \times 10^{-11} = gravitational constant.

   F = \frac{6.674 \times 10^{-11} \times 1.67 \times 10^{-27} \times 9.11 \times 10^{-31}   }{(5 \times 10^{-11} )^{2} }

   F = 4.06 \times 10^{-47} N

Therefore, the gravitational force between proton and an electron is 4.06 \times 10^{-47} N

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