Answer:
The percentage by volume of Oxygen gas in the Trimex blend is 28.2%.
Explanation:
We shall use the formula that connects the mole ratio of a particular gas in a mixture with the partial pressure of that gas and the total pressure of the mixture: which is:
Mole ratio of Oxygen in Trimex = Partial pressure of Oxygen in Trimex divided by the Total pressure of all the gases that made up of Trimex.
Here we go, mole ratio of Oxygen= 55/195. The total pressure is the addition of the partial pressures of all the gases in the Trimex mixture, which is 55+90+50=195.
So the mole ratio of our Oxygen gas will be: 0.282, no unit.
This means we can assume the total moles of all the gas is 1, and oxygen is 0.282.
Since we know that 1 mole of any gas will have 22.4dm cube as volume, then the total volume of the Trimex will be 22.4dm cube, while that of the oxygen gas will be 0.282 X 22.4 dm cube= 6.3179dm cube. Therefore, the percentage by volume of Oxygen gas in the Trimex will be: 6.3179/22.4 X 100 = 28.2%.