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juin [17]
3 years ago
15

Trimix is a general name for a type of gas blend used by technical divers and contains nitrogen, oxygen and helium. In one Trimi

x blend, the partial pressures of each gas are 55 atm oxygen, 90 atm nitrogen, and 50 atm helium. What is the percent oxygen (by volume) in this trimex blend?
Chemistry
2 answers:
Keith_Richards [23]3 years ago
6 0

Answer:

28.2

Explanation:

Add all of the pressures, 55, 90, and 50, and divide 100 by the answer you get (195). You'll get 0.512820513 and multiply it by .55 (atm of Oxygen) and you'll get 28.2

Korolek [52]3 years ago
3 0

Answer:

The percentage by volume of Oxygen gas in the Trimex blend is 28.2%.

Explanation:

We shall use the formula that connects the mole ratio of a particular gas in a mixture with the partial pressure of that gas and the total pressure of the mixture: which is:

Mole ratio of Oxygen in Trimex = Partial pressure of Oxygen in Trimex divided by the Total pressure of all the gases that made up of Trimex.

Here we go, mole ratio of Oxygen= 55/195. The total pressure is the addition of the partial pressures of all the gases in the Trimex mixture, which is 55+90+50=195.

So the mole ratio of our Oxygen gas will be: 0.282, no unit.

This means we can assume the total moles of all the gas is 1, and oxygen is 0.282.

Since we know that 1 mole of any gas will have 22.4dm cube as volume, then the total volume of the Trimex will be 22.4dm cube, while that of the oxygen gas will be 0.282 X 22.4 dm cube= 6.3179dm cube. Therefore, the percentage by volume of Oxygen gas in the Trimex will be: 6.3179/22.4 X 100 = 28.2%.

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eimsori [14]

<u>Answer:</u> The correct answer is Option b.

<u>Explanation:</u>

Reducing agents are defined as the agents which help the other substance to get reduced and itself gets oxidized. They undergo oxidation reaction.

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For determination of reducing agents, we will look at the oxidation potentials of the substance. Oxidation potentials can be determined by reversing the standard reduction potentials.

For the given options:

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This ion cannot be further oxidized because +1 is the most stable oxidation state of silver.

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This metal can easily get oxidized to Pb^{2+} ion and the standard oxidation potential for this is 0.13 V

Pb\rightarrow Pb^{2+}+2e^-;E^o_{(Pb/Pb^{2+})}=+0.13V

  • <u>Option c:</u>  H_2

This metal can easily get oxidized to H^{+} ion and the standard oxidation potential for this is 0.0 V

H_2\rightarrow 2H^++2e^-;E^o_{(H_2/H^{+})}=0.0V

  • <u>Option d:</u>  Ag

This metal can easily get oxidized to Ag^{+} ion and the standard oxidation potential for this is -0.80 V

Ag\rightarrow Ag^{+}+e^-;E^o_{(Ag/Ag^{+})}=-0.80V

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By looking at the standard oxidation potential of the substances, the substance having highest positive E^o potential will always get oxidized and will undergo oxidation reaction. Thus, considered as strong reducing agent.

From the above values, the correct answer is Option b.

8 0
3 years ago
CHEMISTRY HELP PLEASE!
WINSTONCH [101]
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7 0
3 years ago
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An inverted pyramid is being filled with water at a constant rate of 45 cubic centimeters per second. The pyramid, at the top, h
vaieri [72.5K]

Answer:

13.20 cm/s is the rate at which the water level is rising when the water level is 4 cm.

Explanation:

Length of the base = l

Width of the base  =  w

Height of the pyramid = h

Volume of the pyramid = V=\frac{1}{3}lwh

We have:

Rate at which water is filled in cube = \frac{dV}{dt}= 45 cm^3/s

Square based pyramid:

l = 6 cm, w = 6 cm, h = 13 cm

Volume of the square based pyramid = V

V=\frac{1}{3}\times l^2\times h

\frac{l}{h}=\frac{6}{13}

l=\frac{6h}{13}

V=\frac{1}{3}\times (\frac{6h}{13})^2\times h

V=\frac{12}{169}h^3

Differentiating V with respect to dt:

\frac{dV}{dt}=\frac{d(\frac{12}{169}h^3)}{dt}

\frac{dV}{dt}=3\times \frac{12}{169}h^2\times \frac{dh}{dt}

45 cm^3/s=3\times \frac{12}{169}h^2\times \frac{dh}{dt}

\frac{dh}{dt}=\frac{45 cm^3/s\times 169}{3\times 12\times h^2}

Putting, h = 4 cm

\frac{dh}{dt}=\frac{45 cm^3/s\times 169}{3\times 12\times (4 cm)^2}

=13.20 cm/s

13.20 cm/s is the rate at which the water level is rising when the water level is 4 cm.

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